So, first turn your fractions into decimals. ⅞ = 0.875 which rounded is 0.88. 4/5 = 0.8. Next, put the decimals into the equation to replace the fractions. 0.88 + 4.2 - 0.8. Next solve the problem. So 0.88 + 4.2 = 5.08. Now your equation should look like this 5.08 - 0.8. Then subtract 0.8 from 5.08 which gives you 4.28. So 4.28 is your answer.
Surface area of a cuboid
= [2(length)(width)] + [2(width)(height)] + [2(height)(length)]
= {[2(4)(2.5)] + [2(2.5)(2)] + [2(2)(4)]} units²
= (20 + 10 + 16) units²
= 46 units²
Answer:
The frequency of A7, which is two octaves above A5, is 3520 (880 x 2 x 2) Hz. The octave term is used in the musical composition to relate the same notes in the higher or lower scale of notes. The note in the one octave higher scale have a doubled frequency than in the neutral scale and The note in the one octave lower scale have a half frequency than in the neutral scale.
Step-by-step explanation:
MARK BRAINLIEST PLEASE!!!!!!!
What you need to do is multiply both sides by the same number. If 8 times 6 is 48, then 7 times 6 is your answer.
