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alekssr [168]
3 years ago
5

△ABC is a 30-60-90 triangle where m∠B=90° . The length of the shorter leg is 11 units.

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0
Start with where the shorter leg is. It must be opposite the smallest angle.

In a 30 - 60 - 90 degree triangle you have the hypotenuse to be twice as long as the shortest side. You have to read that a couple of times to make sure you understand it. 

That being said, if the shortest side is x, the hypotenuse will be 2x.

Since in this case the shortest side is 11, the hypotenuse will be 2*11 = 22

22 <<<<<< answer.

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4 3/8

Step-by-step explanation:

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Car colors preference change over the years and according to the particular model that the customer selects. In a recent year, 1
Margarita [4]

Answer:

99.05% probabilitiy that at most six cars are black.

Step-by-step explanation:

For each luxury car, there are only two possible outcomes. Either it is black, or it is not black. The probability of a luxury car being black is independent from other luxury cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.1, n = 25

If 25 cars of that year and type are randomly selected, find the probabilitiy that at most six cars are black.

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718

P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994

P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659

P(X = 3) = C_{25,3}.(0.1)^{3}.(0.9)^{22} = 0.2265

P(X = 4) = C_{25,4}.(0.1)^{4}.(0.9)^{21} = 0.1384

P(X = 5) = C_{25,5}.(0.1)^{5}.(0.9)^{20} = 0.0646

P(X = 6) = C_{25,6}.(0.1)^{6}.(0.9)^{19} = 0.0239

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0718 + 0.1994 + 0.2659 + 0.2265 + 0.1384 + 0.0646 + 0.0239 = 0.9905

99.05% probabilitiy that at most six cars are black.

7 0
3 years ago
Evaluate each expression. 16 5/4 x 16 1/4 / (16 1/2)/2= ​
Fiesta28 [93]

Answer: the answer is 4

Step-by-step explanation:

3 0
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