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olchik [2.2K]
2 years ago
15

Need help po, needed today. Thanks! ​

Mathematics
1 answer:
Dimas [21]2 years ago
8 0

Answer:

<h2>question is not up down this is incorrect questions</h2>
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The perimeter of a rectangular deck is 4 times its width. If the deck's perimeter is 30 feet, what is the deck's area?
RSB [31]

Answer:

i think it is 120

Step-by-step explanation:

4 multiplied by 30 is 120

4 0
3 years ago
Please help please i really need help
vodomira [7]

Answer:

78

Step-by-step explanation:

help me with mine pls your smart

8 0
3 years ago
Law of sines: Which equation is correct and can be used to solve for the value of z?
nikdorinn [45]

The answer is A. I just finished the test.

7 0
3 years ago
Read 2 more answers
Karita had $138.72 in her checking account. She wrote checks for $45.23 and $18.00. Then she made a deposit of $75.85 into her a
svetlana [45]

Answer:

The best estimate for the money in Karita's account now is $151.

Step-by-step explanation:

Given:

Karita had $138.72 in her checking account.

She wrote checks for $45.23 and $18.00.

Then she made a deposit of $75.85 into her account.

Now, to find the best estimate for the money in Karita's account now.

<em>Initial account = $138.72.</em>

<em>Deducted amount = $45.23+$18.00=$63.23.</em>

So, the amount after deduction:

$138.72 - $63.23 = $75.49.

Now, the amount after deposit:

$75.49 + $75.85 = $151.34.

Therefore, the best estimate for the money in Karita's account now is $151.

6 0
3 years ago
For a population with µ = 80 and σ = 20, the Sampling distribution of the Mean, based on n = 16 will have an expected value of t
allsm [11]

Answer:

Will have an expected value of the mean = 80 and a standard error of the mean = 5

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 80, \sigma = 20

n = 16

So the mean is 80 and the standard deviation is s = \frac{20}{\sqrt{16}} = 5

Will have an expected value of the mean = 80 and a standard error of the mean = 5

6 0
3 years ago
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