A grating has 320 lines/mm. How many orders of the visible wavelength 551 nm can it produce in addition to the m = 0 order
1 answer:
Answer:
6
Explanation:
Given that
dsinθ = mλ,
now, if sinθ = 1, then
m = d / λ, where
m = order of interference
d = distance between the slits
λ = wavelength of light
this is the formula we would use to solve the question
d = 1 / 320 lines/mm
d = 1 / 320*10^3
d = 3.125*10^-6 m
At λ = 551 nm, we have
m = 3.125*10^-6 / 551*10^-9
m = 5.67
5.67 ~ 6
thus, we can say that the orders of visible wavelength 551 nm, can produce is 6
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