Answer:
188 A
Explanation:
Parameters given:
Length of cable, L = 0.78 m
Angle, θ = 60º
Magnetic field, B = 5.5 * 10^(-5) T
Force experienced by wire, F = 7 * 10^(-3) N
The force experienced by a current carrying wire of length L, due to a magnetic field B is given as:
F = I * L * B * sinθ
=> I = F/(L * B * sinθ)
I = (7 * 10^(-3)) / (0.78 * 5.5 * 10^(-5) * sin60)
I = 188 A
Answer:
A) - 1.8 m/s
Explanation:
As we know that whole system is initially at rest and there is no external force on this system
So total momentum of the system must be conserved
so we will have
now plug in all data into above equation
so correct answer is
A) - 1.8 m/s
Answer: Option D: 5.5×10²Joules
Explanation:
Work done is the product of applied force and displacement of the object in the direction of force.
W = F.s = F s cosθ
It is given that the force applied is, F = 55 N
The displacement in the direction of force, s = 10 m
The angle between force and displacement, θ = 0°
Thus, work done on the object:
W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J
Hence, the correct option is D.
Explanation:
B. leads to muscle strain.
