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lord [1]
2 years ago
6

Một tải có điện trở R = 19ohm đấu vào nguồn điện một chiều có E = 100V,

Physics
1 answer:
klio [65]2 years ago
6 0

Answer:

Hindi ko alma yam among twang yan

Explanation:

aorry

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Write two units for electric field intensity and show thier equivalence?​
nataly862011 [7]

Answer:

Electric field intensity is the force experienced by a test charge q in a electric field E.

7 0
3 years ago
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What is the unit for electrical power?
Vaselesa [24]

Answer:

The answer is Watt

Explanation:

Electricity is measured in Watts and kilowatts

Electricity is measured in units of power called Watts, named to honor James Watt, the inventor of the steam engine. A Watt is the unit of electrical power equal to one ampere under the pressure of one volt. One Watt is a small amount of power.

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3 years ago
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Can someone please help me?
Luba_88 [7]

Answer:

1525 meters above ground

Explanation:

So to do this you will need to write this in slope intercept form or y=mx+b. So 650 would be the b, 175 would be the m, and the x would be 5 so the equation would be y=175(5)+650 so if you solve or simplify the equation you will get 1525 meters above the ground and that would be our final answer.

5 0
2 years ago
Some planetary scientists have suggested that the planet Mars has an electric field somewhat similar to that of the earth, produ
aalyn [17]

Answer:

324795 C

252.637820565 N/C

2.235844712\times 10^{-9}\ C/m^2

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

R = Radius of Mars = 3.4\times 10^6\ m

A = Area = 4\pi R^2

\phi = Electric flux = 3.67\times 10^{16}\ Nm^2/C

Electric flux is given by

\phi=\dfrac{q}{\epsilon_0}\\\Rightarrow q=\phi\epsilon_0\\\Rightarrow q=3.67\times 10^{16}\times 8.85\times 10^{-12}\\\Rightarrow q=324795\ C

The charge is 324795 C

Electric field is given by

E=\dfrac{\phi}{A}\\\Rightarrow E=\dfrac{3.67\times 10^{16}}{4\pi (3.4\times 10^6)^2}\\\Rightarrow E=252.637820565\ N/C

The electric field is 252.637820565 N/C

Surface charge density is given by

\sigma=\dfrac{q}{4\pi R^2}\\\Rightarrow \sigma=\dfrac{324795}{4\pi (3.4\times 10^6)^2}\\\Rightarrow \sigma=2.235844712\times 10^{-9}\ C/m^2

The surface charge density is 2.235844712\times 10^{-9}\ C/m^2

6 0
3 years ago
27 miles per gallon into kilometers per liter.
ikadub [295]

Answer:

11.479 kilometres per litre

Explanation:

for an approximate result, divide the fuel economy value by 2.352

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3 years ago
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