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Nana76 [90]
3 years ago
13

Could someone just show me how to do it? i don't want the answer just an example of how to do it

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0

Calculating radicals can be difficult if they don't work out. To calculate a radical that doesn't work out, you can estimate by finding which two perfect square roots it lies between. You can also use a calculator.

An alternative solution, using properties of square roots is where \sqrt{(a*b)} = \sqrt{a} * \sqrt{b}

Using this, we can create 2\sqrt{3}\\=\sqrt{4*3}\\=\sqrt{12}. This is between the perfect square 9 and 16 (3 and 4).

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S/4 -7 =9<br> any help solving this question?
sasho [114]

Answer:

S=64

Step-by-step explanation:

if the s is what your looking for

5 0
3 years ago
Read 2 more answers
Factorize:<br> 2ax-6ay+bx-3by
Elodia [21]

Answer:

2ax − 6ay + bx − 3

Step-by-step explanation:

The expression is not factorable with rational numbers

3 0
3 years ago
Read 2 more answers
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B10%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B5%7D%20" id="TexFormula1" title=" \fr
Nimfa-mama [501]
You may solve this ratio by cross multiplying. To do this, you multiply the numbers diagonally across from each other.

    x/10 = 1/5
    10(1) = x(5)
        10 = 5x
          2 = x

Answer:
x = 2
4 0
3 years ago
A restaurant offers 7 appetizers and 8 main courses. In how many ways can a person order a two-course meal?
VLD [36.1K]

Answer:

56

Step-by-step explanation:

so 7 appetizers times 8 main courses

I do a easy trick where I multiple so

7×8=56

4 0
2 years ago
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