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Solnce55 [7]
3 years ago
12

You are selling your product at a three-day event. Each day, there is a 60% chance that you will make money. What is the probabi

lity that you will make money on the first two days and lose money on the third day
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Answer:

The required probability = 0.144

Step-by-step explanation:

Since the probability of making money is 60%, then the probability of losing money will be 100-60% = 40%

Now the probability we want to calculate is the probability of making money in the first two days and losing money on the third day.

That would be;

P(making money) * P(making money) * P(losing money)

Kindly recollect;

P(making money) = 60% = 60/100 = 0.6

P(losing money) = 40% = 40/100 = 0.4

The probability we want to calculate is thus;

0.6 * 0.6 * 0.4 = 0.144

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Answer:

DE = 7.07 RS = 11.04 not congruent

Step-by-step explanation:

Formula:

d=\sqrt{(x2-x1)^2 + (y2-y1)^2}

D (5,0) E (0,-5)

DE

d=\sqrt{(0-5)^2 + ( -5 - 0)^2}

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d=\sqrt{(6-(-5))^2 + (-6 - (-5))^2 }

d=\sqrt{11^2 + (-1)^2}

d=\sqrt{121 + 1}

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2 years ago
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Please read the whole thing.

Step-by-step explanation:

Hi. For this problem you are going to combine like terms.

For these problems, if you need any more help, you can search up algebra calculators on google.

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