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masha68 [24]
3 years ago
15

What is the approximate value of the function at x = -4?

Mathematics
1 answer:
umka21 [38]3 years ago
6 0
The approximate value of the function at x=-4 according to the function is B)1.8
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The system of equations is graphed on the coordinate plane.
ehidna [41]

Answer: The solution is (3, -2)

This means that x = 3 and y = -2 pair up together.

=====================================================

Explanation:

The solution is where the two lines cross. Note if we started at the origin (0,0) and moved to the right 3 units, and then down 2 units, we would arrive at the location (3, -2).

-----------------

As a way to check, we can plug x = 3 into each equation. We should get y = -2 as a result for each equation

y = (-5/3)x + 3

y = (-5/3)*3 + 3

y = -5+3

y = -2

The first equation is confirmed. Let's check the second equation

y = (1/3)x - 3

y = (1/3)*3 - 3

y = 1 - 3

y = -2

Both equations have the y value equal -2 when x = 3. Therefore, the overall solution is confirmed.

3 0
3 years ago
What is the area of the figure below?
Lerok [7]

Answer:

The answer is 58 In2

you can take apart some of the parts and multiply them, it may be easier

6 0
3 years ago
Which pair of ratios forms a proportion?​
bogdanovich [222]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
dylan started working on homework at 5:45 p.m. it took him 1 hour and 57 minutes to complete it what time did
kkurt [141]

I'm assuming its asking what time he finished? I added it up and it seems to be 7:42 pm.

5 0
3 years ago
Find the distance UV between the points U(4,−2) and V(6,−1). Round your answer to the nearest tenth, if necessary.
Liono4ka [1.6K]

The horizontal distance is the difference of x-coordinates: 6 - 4 = 2.

The vertical distance is the difference of y-coordinates: -1 - (-2) = 1.

The straight-line distance (d) can be found using the Pythagorean theorem, since the vertical and horizontal distances are at right angles to each other.

.. d² = 2² + 1² = 5

.. d = √5 ≈ 2.2

The distance UV is about 2.2.

8 0
3 years ago
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