James and Bethany Morrison are celebrating their 10th anniversary by having a reception at a local reception hall. They have
1 answer:
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Let
A------> <span>(1, 4)
B------> (6, 4)
C-----> (6,1)
we know that
In </span><span>a right triangle there are two legs and one hypotenuse
</span><span>
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> d=√[(4-4)²+(6-1)²]-----> d=√25----> 5
AB=5 units
step 2
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-6)²]-----> d=√9----> 3
BC=3 units
step 3
find the distance AC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-1)²]-----> d=√34----> 5.83
AC=5.83 units
therefore
the two legs are
AB=5 units
BC=3 units
the hypotenuse is
AC=5.83 units
the answer is
<span>the length of the longer leg is AB=5 units
</span>
see the attached figure
A------> <span>(1, 4)
B------> (6, 4)
C-----> (6,1)
we know that
In </span><span>a right triangle there are two legs and one hypotenuse
</span><span>
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> d=√[(4-4)²+(6-1)²]-----> d=√25----> 5
AB=5 units
step 2
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-6)²]-----> d=√9----> 3
BC=3 units
step 3
find the distance AC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-1)²]-----> d=√34----> 5.83
AC=5.83 units
therefore
the two legs are
AB=5 units
BC=3 units
the hypotenuse is
AC=5.83 units
the answer is
<span>the length of the longer leg is AB=5 units
</span>
see the attached figure