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DedPeter [7]
3 years ago
9

- For any nonquadrantal angle 0, sin 0 and csc 0 will have the same sign explain why

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

Because sin 0 and csc 0 establish a relationship where one is reciprocated to the other.

Step-by-step explanation:

Sin 0 is found according to the mathematical expression Sin 0 = y / r.

The csc 0, in turn, is found through the mathematical expression Csc 0 = 1 / sin 0, which is equivalent to y / r.

In both expressions the letter "r" will always be represented by a positive value. This makes Csc 0 and sin 0 have a strong reciprocity and assume the same sign, regardless of the number that represents the "Y". This is because if "y" has a positive value, both sin 0 and csc 0 will have a positive sign, if "Y" will take a negative value, both sin 0 and csc 0 will take negative signs.

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Which equation represents the total price (p) paid when buying books (b) that cost $3.99 each? How much do 13 books cost?
Mariana [72]

Answer:

Your answer is D p=3.99;$51.87

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
11 –2<br><br> · <br> 3 –4<br><br> · <br> 6 2<br><br> =
Sav [38]

Answer: negative 243

11 - 2 x 3 - 4 x 62 =

11 - 6 - 4 x 62=

11 - 6 - 248=

5 - 248=

-243

4 0
3 years ago
Read 2 more answers
First question, thanks. I believe there should be 3 answers
zysi [14]

Given: The following functions

A)cos^2\theta=sin^2\theta-1B)sin\theta=\frac{1}{csc\theta}\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}

B

\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}

C

\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}

D

\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}

E

\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}

Hence, the following are identities

\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

The marked are the trigonometric identities

3 0
1 year ago
When Justin goes to work, he drives at an average speed of 65 miles per hour. It takes about 1 hour and 30 minutes for Justin to
Fofino [41]

Answer:

Justin spends $14.24 on gas to travel to work.

Step-by-step explanation:

Given:

Average speed at which Justin goes to work = 65 miles/hour

Time taken by Justin to arrive at work = 1 hour and 30 minutes = 1.5 hours [As 30 minutes =0.5 hours]

Distance he can travel per gallon of gas = 25 miles.

Cost of per gallon of gas = $3.65

Solution:

We first determine the distance Justin travels to work.

Distance = Speed\times time

Distance = 65\times 1.5 = 97.5\ miles

Using unitary method to find the amount of gas required to cover the distance.

If 25 miles is covered in 1 gallon of gas

Then 1 mile will be covered in = \frac{1}{25} gallons of gas

So, to cover 97.5 miles gas required = \frac{1}{25}\times 97.5=3.9 gallons of gas.

Using unitary method to find the cost of 3.9 gallons of gas.

Cost of 1 gallon of gas = $3.65

So, cost of 3.9 gallons of gas will be = \$3.65\times 3.9=\$14.235\approx\$14.24 (Answer)

3 0
3 years ago
3 gallons = 48 cups
seraphim [82]

Answer:

Yes that's correct!! Nice work!! (: You're doing great.

Step-by-step explanation:

6 0
3 years ago
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