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kap26 [50]
3 years ago
7

Please answer ASAP. The question is down below

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:  1) D      2) B

<u>Step-by-step explanation:</u>

1) The denominator cannot equal zero, Factor the denominator to find the zeros.  n³ - 4n² + 3n = 0

           n(n - 3)(n - 1) = 0

       n=0  n-3=0   n-1=0

       n=0    n=3      n=1

2) In order to be a rational expression, it must be in the form \dfrac{a}{b} where both a and b are integers.

Since \sqrtb\sqrt b is irrational and not an integer, then the expressions containing an irrational term <em>after simplified</em> cannot result in an integer.

Therefore, options <em>(i)</em> and <em>(iv)</em> are not rational expressions.

Option <em>(iii)</em> contains b as an exponent.  Since there is no information about b, it could be a fraction, which means it could be an irrational number.

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