V=(4/3)pir^3
find smaller
V=(4/3)pi8^3
V=(4/3)pi512
V=(2048/3)pi
twice of that
Vbig=2*(2048/3)pi
Vbig=(4096/3)pi
find radius
(4096/3)pi=(4/3)pir^3
divide both sides by pi
(4096/3)=(4/3)r^3
times both sides by 3
4096=4r^3
divide both sides by 4
1024=r^3
cube root both sides
8∛2=r
aprox
10.0794
the answer you are looking for is 8∛2 or 10.0794in or something close to that
Collinear points are two or more points that lie on the same line.
this question came out in a juniour olympiad nigeria
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It has to be noted that there are several ways to factor the item. One of these is shown below.
The general form of a quadratic equation is,
Ax² + Bx + C = 0
where A and B are numerical coefficients and C is the constant. If we are to express the given equation in this form,
2x² - 5x - 88 = 0
The sum of the roots, x₁ and x₂ is -B/A and the product is equal to C/A.
Sum: x₁ + x₂ = -(-5/2) = 5/2
Product: x₁x₂ = -88/2 = -44
The values of x₁ and x₂ are 8 and -11/2.
The factors are (x - 8) and (x + 11/2)
<em>ANSWERS: 8 and -11/2. </em>
Answer:
a.
b.
Step-by-step explanation:
We are given that
a.Substitute z=0
...(1)
..(2)
Subtract equation (1) from equation (2)
Substitute y=0 in equation(1)
The point (6,0,0) lie on a line.
Let 
Therefore, the vector 
Line is parallel to vector a' and passing through the point (6,0,0).
The parametric equation is given by
Using the formula
The parametric equation is given by
Angle between two plane
and 
Using the formula
Where 
in degree.
