Answer:
i dont understand this qustion\
Step-by-step explanation:
Vertex: (2,1)
axis of symmetry: (0,2)
direction of opening: up
not sure what optimal value is.
y-intercept: (0,5)
not sure what the step pattern is.
Answer:
i think you put the 7.3X2+9.1 then divided it by 8.7 -6.1
Step-by-step explanation:
let me see if i can help you
Answer:
132°
Step-by-step explanation:
Angle JKH and IHK are alternate interior angles, and thus congruent.
Since JKH is 132 degrees, so is IHK
The problem is to optimize (find the maximum The problem is to maximiz the function
<span>f(x,y,z)=xyz </span>
<span>With the constrain </span>
<span>2(xy + xz + yz)=64; xy+xz+yz=32 </span>
<span>Using the Lagrange Multipliers </span>
<span>F(x,y,z) = xyz - £(xy+xz +yz-32) </span>
<span>Deriving with respect to x: </span>
<span>yz - £(y+z)=0 ....i</span>
<span>Deriving with respect to y: </span>
<span>xz - £(x+z)=0 ...ii</span>
<span>Deriving with respect to z: </span>
<span>xy - 2£(x+y)=0 ....iii</span>
<span>Deriving with respect to £: </span>
<span>xy+xz+yz=32 .....iv</span>
<span>From (i) and (ii) </span>
<span>yz/2(y+z) = xz/2(x+z) </span>
<span>y/(y+z) = x/(x+z) </span>
<span>yx+yz=xy+xz </span>
<span>y=x </span>
<span>From (i) and (iii) </span>
<span>x=z </span>
<span>So, from (iv) </span>
<span>x^2+x^2+x^2=32 </span>
<span>x^2=32/3 </span>
<span>x=y=z=sqrt (32/3) </span>
<span>Vmax = sqrt (32/3)^3 </span>
