All categories

3 years ago

6n What is the value of the expression when N=7

Mathematics

2 answers:

zysi [14]3 years ago

7 0

42 is the right answer

dezoksy [38]3 years ago

5 0

Answer:

Step-by-step explanation:6n(n=7)

6(7) or 6•7, which equals 42

You might be interested in

An equation of a trend line for the scatter plot below is y=42x+50. Predict how many more sales the store makes in December than

Mars2501 [29]

Answer:

42 more sales in December

Step-by-step explanation:

3 0

3 years ago

Solve the equation. -7 = -1 + x/3

pochemuha

Answer:

x= -18

Step-by-step explanation:

We want to isolate x ( move everything to the other side of the equation)

-7 = -1 + x/3

-6 = x/3

x= 3*-6

x= -18

6 0

3 years ago

Read 2 more answers

6. a. Name a pair of equations that have exactly one point of intersection. How do you know?

True [87]

Answer:

A system of linear equations will have exactly one point of intersection, for example:

2x+y=5

-x+y=2

However, a system of linear equations with no solution will have no points of intersection, for example:

-4x+10y=6

2x-5y=3

Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe

And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)

I attached a photo below, and one of how to graph it

4 0

2 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

Find the length of the segment AB

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

Find the cosine of the angle BAD

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

Find the length of the segment AC

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

Find the length of the segment DC

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

Find the length of the segment BC

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

the answer is

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

If a= 35 then find b

KengaRu [80]

9514 1404 393

Answer:

Step-by-step explanation:

All of the marked angles subtend the same arc, so all have the same measure.

a = b = c = d = 35

b = 35

8 0

3 years ago