All categories

4 years ago

Please help me answer this question

Chemistry

2 answers:

abruzzese [7]4 years ago

7 0

Answer:

Electrolytes are observed by conductivity - so unknown 2 should be circled, and Tap Water, which almost always contains electrolytes, mineral salts in solution.

Explanation:

Schach [20]4 years ago

5 0

Electrolytes are observed by conductivity. unknown 2 should be circled, and Tap Water.

You might be interested in

Are bacteria multiple-celled microscopic organisms .true or false

deff fn [24]

Answer:

Bacteria are multiple-celled microscopic organisms. It's gross but Fungi is the most abundent form of life on Earth.

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

7 0

3 years ago

What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115 g of

Citrus2011 [14]

Answer:

freezing point (°C) of the solution = - 3.34° C

Explanation:

From the given information:

The freezing point (°C) of a solution can be prepared by using the formula:

$\Delta T = iK_fm$

where;

i = vant Hoff factor

the vant Hoff factor is the totality of the number of ions in the solution

Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3

$K_f$ = 1.86 °C/m

m = molality of the solution and it can be determined by using the formula

$molality = \dfrac{mole \ of \ solute }{kg \ of \ solvent }$

which can now be re-written as :

$molality = \dfrac{mole \ of \ Ca(NO_3)_2}{kg \ of \ water}$

$molality = \dfrac{\dfrac{mass \ of \ \ Ca(NO_3)_2}{molar \ mass of \ Ca(NO_3)_2} }{kg \ of \ water}$

$molality = \dfrac{\dfrac{11.3 \ g }{164 \ g/mol} }{0.115 \ kg }$

molality = 0.599 m

∴

The freezing point (°C) of a solution can be prepared by using the formula:

$\Delta T = iK_fm$

$\Delta T =3 \times (1.86 \ ^0C/m) \times (0.599 \ m)$

$\Delta T =3.34^0 \ C$

$\Delta T =$ the freezing point of water - freezing point of the solution

3.34° C = 0° C - freezing point of the solution

freezing point (°C) of the solution = 0° C - 3.34° C

freezing point (°C) of the solution = - 3.34° C

3 0

3 years ago

When a 1.0 M KCl solution is electrolyzed using silver electrodes, a precipitate forms at the anode. Explain this result please.

Nady [450]

Hope this answer will help you

5 0

3 years ago

Which ligand binds the tightest? Ligand A, with a Kd of 10^-9M Ligand B, with a Kd of 10^-3M Ligand C, with a percent occupancy

padilas [110]

To answer this item, we must take note that the ligand that binds the tightest is the one with the lowest dissociation constant, Kd. Kd's for both A and B are already given so, we only need to solve Kds for C and D.
Kd of C
0.3 = (1x10⁻⁶)/(1x10⁻⁶ + Kd) ; Kd = 2.3x10⁻⁶
Kd of D
0.8 = (1x10⁻⁹)/(1x10⁻⁹ + Kd) ; Kd = 2.5x10⁻10
Since Ligand D has the least value of dissociation constant then, it can be concluded that it binds the tightest.

6 0

3 years ago

A contour line connects points of the same _____.

Shkiper50 [21]

Answer:

the answer is elevation

3 0

4 years ago

Read 2 more answers