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faltersainse [42]
3 years ago
12

Please help me answer this question

Chemistry
2 answers:
abruzzese [7]3 years ago
7 0

Answer:

Electrolytes are observed by conductivity - so unknown 2 should be circled, and Tap Water, which almost always contains electrolytes, mineral salts in solution.

Explanation:

Schach [20]3 years ago
5 0

Electrolytes are observed by conductivity. unknown 2 should be circled, and Tap Water.

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If you had excess aluminum, how many moles of aluminum chloride could be produced from 21.0 g of chlorine gas, cl2?
AleksandrR [38]
When aluminum metal is made to contact with chlorine gas (Cl₂), a highly exothermic reaction proceeds. This produces aluminum chloride (AlCl₃) powder. The balanced chemical equation for this reaction is shown below:

2Al(s) + 3Cl₂(g) → 2AlCl₃(s)

Since it was stated that aluminum is in excess, this means that the amount of AlCl₃ produced will only depend on the amount of Cl₂ gas available. The molar mass of Cl₂ is 70.906 g/mol. Using stoichiometry, we have the following equation:

(21.0 g Cl₂/ 70.906 g/mol Cl₂) x 2 mol AlCl₃/ 2 mol Cl₂ = 0.1974 mol AlCl₃

Thus, we have determined that 0.1974 <span>moles of aluminum chloride can be produced from 21.0 g of chlorine gas. </span>
3 0
3 years ago
ILL GIVE BRAINLIEST
Mice21 [21]

Answer:

Which of the following happens during a lunar eclipse?

Select one:

a. Earth casts a shadow on the moon.

<u>b. The moon casts a shadow on Earth. </u>

c. Earth stops revolving in its orbit.

d. Earth starts revolving around the moon.

Explanation:

7 0
3 years ago
Any integrated chem buffs out there?
marusya05 [52]

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5 0
3 years ago
An adult mosquitoes lifespan is about 16 days how many minutes is that
Delicious77 [7]
1 day = 1, 440 minutes
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5 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
3 years ago
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