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charle [14.2K]
3 years ago
6

What is the base ionization constant expression for ammonia?

Chemistry
1 answer:
4vir4ik [10]3 years ago
7 0

Explanation:

Kb: The base ionization constant

2) Ammonia (formula = NH3) is the most common weak base example used by instructors. ... This constant, Kb, is called the base ionization constant. It can be determined by experiment and each base has its own unique value. For example, ammonia's value is 1.77 x 10¯5.

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A sample of 4.5 moles of hydrogen is used to react how many grams of nitrogen trihydride will be produced
GaryK [48]

Answer:

51.1 g NH3

The required chemical reaction is given by:

N2 + 3H2 --> 2NH3

4.5 mol H2 × (2 mol NH3/3 mol H2) = 3 mol NH3

molar mass of NH3 is 17.031 g/mol

3 mol NH3 × (17.031 g NH3/1 mol NH3) = 51.1 g NH3

5 0
3 years ago
2a) Name two elements Found in waler.
OverLord2011 [107]

Answer:

Hydrogen and Oxygen

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6 0
3 years ago
How many grams of aluminum chloride can be produced from 7.32g of ammonium perchlorate?
Alla [95]

Answer:

2.77g of AlCl_{3} can be produced.

Explanation:

Use stoichiometry.

Balanced equation: 3Al + 3NH_{4} ClO_{4} ⇒ Al_{2} O_{3} + AlCl_{3} +3NO + 6H_{2} O

NH_{4} ClO_{4}  :  AlCl_{3}

      3        :     1                        **n=\frac{m}{M}

 0.0623**   :    x                        n=\frac{7.32}{117.49}   = 0.0623

      3x=0.0623\\x=0.020767

n=\frac{m}{M}    

m=nM

m= (0.020767)(133.34)

m= 2.77g                                  

5 0
2 years ago
How many electrons does carbon have if it has six protons?
lidiya [134]

it is 6, all isotopes of carbon have 6 electrons and 6 protons which is why its atomic number is 6

4 0
3 years ago
3- a) write the formula unit of calcium fluoride.
zvonat [6]

Answer:

a) CaF₂.

b) 7.81g of CaF₂ are present.

Explanation:

a) The calcium ion has as charge Ca²⁺ and fluoride ion is F⁻, that means formula unit is:

CaF₂

b) 1 molecule of CaF₂ contains 2 anions, F⁻. Thus, the moles of CaF₂ is:

1.2x10²³ anions * (1 moleculeCaF₂ / 2 anions) = 6x10²² molecules of CaF₂

6.022x10²³ molecules = 1mol:

6x10²² molecules of CaF₂ * (1mol / 6.022x10²³molecules) = 0.10 moles CaF₂.

1 mole of CaF₂ has a mass of 78.07g:

0.10 moles CaF₂ * (78.07g / mol) =

7.81g of CaF₂ are present

5 0
3 years ago
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