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ZanzabumX [31]
3 years ago
10

Which statement correctly compares an atom of an alkali metal with an atom of the alkaline earth metal next to it on the periodi

c table?
Chemistry
1 answer:
Mumz [18]3 years ago
6 0
<span>The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion. hope this helps</span>
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CalcuLate the velocity of an electron ejected if 300.0 mm of light is applied to the surface. A wavelength of 795 nm has suffici
worty [1.4K]
The equation relating velocity and wavelength is written below:

v = λf
where λ is the wavelength in m while f is frequency in 1/s.

Let's determine first the frequency from the speed of light:
c = distance/time, where c is the speed of light equal to 3×10⁸ m/s
3×10⁸ m/s = (300 mm)(1 m/1000 mm)/ time
time = 1×10⁻⁹ seconds
Since f = 1/t,
f = 1/1×10⁻⁹ seconds = 10⁹ s⁻¹

Thus,
v = (795×10⁻⁹ m)(10⁹ s⁻¹)
v = 795 m/s
8 0
3 years ago
Scientists are testing a new drug, which they think might allow people to memorize large amounts of information. Group A is taki
musickatia [10]
The answer to this question is C: the ability to memorize

Hope this helps :)
6 0
3 years ago
Read 2 more answers
The viscosities of several liquids are being compared. All the liquids are poured down a slope with equal path lengths. The liqu
boyakko [2]

Explanation:

The property of a substance to resist the flow of motion is known as viscosity. And, more is the density of a substance more will be its viscosity.  

Whereas, lesser is the density of a substance then it is easy for the substance to move.

This means that more is the viscosity of a substance least will be its flow and when a substance has lesser viscosity then it will readily flow from one point to another.

Thus, we can conclude that the viscosities of several liquids are being compared. All the liquids are poured down a slope with equal path lengths. The liquid with the highest viscosity will reach the bottom last.

8 0
3 years ago
A 10 mm Brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a) Compute the HB of this mat
Lady_Fox [76]

Explanation:

(a)  The given data is as follows.  

         Load applied (P) = 1000 kg

         Indentation produced (d) = 2.50 mm

         BHI diameter (D) = 10 mm

Expression for Brinell Hardness is as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

(b)     The given data is as follows.

               Brinell Hardness = 300

                Load (P) = 500 kg

               BHI diameter (D) = 10 mm

             Indentation produced (d) = ?

                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

5 0
3 years ago
Find the volume of a gas if 3.6 mols of the gas is at STP
Digiron [165]

Answer:

81 L gas

General Formulas and Concepts:

<u>Ideal Gas Law</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.6 mols gas at STP

[Solve] volume (L) of gas

<u>Step 2: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.6 \ mol \ gas(\frac{22.4 \ L \ gas}{1 \ mol \ gas \ at \ STP})
  2. [DA] Multiply [Cancel out units]:                                                                      \displaystyle 80.64 \ L \ gas

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

80.64 L gas ≈ 81 L gas

6 0
3 years ago
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