Answer:
a) 29
b) 0
c) 7
d) 3/8
Step-by-step explanation:
Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.
If the result is negative, you add the clock hours.
a) 21 - 33 = -12 , so -12 + 41 = 29
b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.
c) 11+19 = 30, 30 - 23 = 7
d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.
We have two unknowns: x and y. Now, we have to formulate 2 equations. The first would come from the use of the given ratio:
We use the distance formula to find the distance between coordinates:
3/4 = √[(x-4)²+(y-1)²] / √[(4-12)²+(1-5)²]
√[(x-4)²+(y-1)²] = 3√5
(x-4)²+(y-1)² = 45
x² - 8x + 16 + y² - 2y + 1 = 45
x² - 8x + y² - 2y = 28 --> eqn 1
The second equation must come from the equation of a line:
y = mx +b
m = (5-1)/(12-4) = 1/2
Substitute y=5 and x=12 for point (12,5)
5 = (1/2)(12) + b
b = -1
So, the second equation is
y = 1/2x -1 or x = 2 + 2y --> eqn 2
Solving the equations simultaneously:
(2 + 2y)² - 8(2 + 2y) + y² - 2y = 28
Solving for y,
y = -2
x = 2+2(-2) = -2
Therefore, the coordinates of point A is (-2,-2).
Answer:
x = -7
Step-by-step explanation:
Answer:
iii. (l + m - n)(l - m + n)
vi. (5a -b) ( 5b - a)
Step-by-step explanation:
iii. l² - (m - n)²
= (l + m - n)(l - m + n)
vi. 4(a+b)² - 9(a-b)²
= (2(a+b))² - (3(a-b))²
= (2(a+b) + 3(a-b)) (2(a+b) - 3(a-b))
= (2a+2b + 3a - 3b) (2a+2b - 3a + 3b)
= (5a -b) ( 5b - a)
Answer:
y-5=0
Step-by-step explanation:
(eliminate the opposites)
y-5=5-5
Solution is y-5=0