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balandron [24]
3 years ago
10

Find tan0, cos0, and csc0, where 0 is the angle shown in the figure. Give exact values, not decimal approximations. BRANLIEST!!​

Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

We require to find the third side of the triangle.

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x represent the third side, then

x² + 15² = 17², that is

x² + 225 = 289 ( subtract 225 from both sides )

x² = 64 ( take the square root of both sides )

x = \sqrt{64} = 8

Thus

tanΘ = \frac{opposite}{adjacent} = \frac{15}{8}

cosΘ = \frac{adjacent}{hypotenuse} = \frac{8}{17}

sinΘ = \frac{opposite}{hypotenuse} = \frac{15}{17}

cscΘ = \frac{1}{sin0} = \frac{1}{\frac{15}{17} } = \frac{17}{15}

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Answer:

32 one-dollar bills.

Step-by-step explanation:

Let <em>x </em>represent one-dollar bills and <em>y </em>represent two-dollar bills.

He has a total of 49 bills. Therefore:

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The total amount of money James has is 66. <em>x</em> is worth one dollar, while <em>y</em> is worth two dollars. Therefore:

1x+2y=66\\x+2y=66

We have a system of equations. Solve by substitution:

x+2y=66\\x+y=49\\x=49-y\\(49-y)+2y=66\\y=17\\x=49-17=32

Therefore, James has 32 one-dollar bills and 17 two-dollar bills.

Checking:

32(1)+17(2)\stackrel{?}{=}66\\32(1)+17(2)\stackrel{\checkmark}{=}66\\\\32+17\stackrel{?}{=}49\\49\stackrel{\checkmark}{=}49

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