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balandron [24]
3 years ago
10

Find tan0, cos0, and csc0, where 0 is the angle shown in the figure. Give exact values, not decimal approximations. BRANLIEST!!​

Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

We require to find the third side of the triangle.

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x represent the third side, then

x² + 15² = 17², that is

x² + 225 = 289 ( subtract 225 from both sides )

x² = 64 ( take the square root of both sides )

x = \sqrt{64} = 8

Thus

tanΘ = \frac{opposite}{adjacent} = \frac{15}{8}

cosΘ = \frac{adjacent}{hypotenuse} = \frac{8}{17}

sinΘ = \frac{opposite}{hypotenuse} = \frac{15}{17}

cscΘ = \frac{1}{sin0} = \frac{1}{\frac{15}{17} } = \frac{17}{15}

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