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balandron [24]
3 years ago
10

Find tan0, cos0, and csc0, where 0 is the angle shown in the figure. Give exact values, not decimal approximations. BRANLIEST!!​

Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

We require to find the third side of the triangle.

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x represent the third side, then

x² + 15² = 17², that is

x² + 225 = 289 ( subtract 225 from both sides )

x² = 64 ( take the square root of both sides )

x = \sqrt{64} = 8

Thus

tanΘ = \frac{opposite}{adjacent} = \frac{15}{8}

cosΘ = \frac{adjacent}{hypotenuse} = \frac{8}{17}

sinΘ = \frac{opposite}{hypotenuse} = \frac{15}{17}

cscΘ = \frac{1}{sin0} = \frac{1}{\frac{15}{17} } = \frac{17}{15}

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The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.

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Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39

Now the lowest 80% of the amount invested can be represented as follows:

P(\bar X

The value of <em>z</em> is 0.84.

*Use a <em>z</em>-table.

Compute the value of the mean amount invested as follows:

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Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

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