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pantera1 [17]
3 years ago
13

A typical eukaryotic cell that has an abundant supply of glucose and O2 will generate a proton gradient in its mitochondria by _

___ that is used primarily for ____.
Chemistry
1 answer:
posledela3 years ago
5 0

Answer:

A typical eukaryotic cell that has an abundant supply of glucose and O2 will generate a proton gradient in its mitochondria by <u>the electron transport chain</u> that is used primarily for <u>chemiosmosis</u>

Explanation:

<u><em>Some terms explained</em></u>

<em>Eukaryotic cells</em> are cells that contain a nucleus and organelles, and are enclosed by a plasma membrane and whose DNA is bound together by proteins into well-defined chromosomes (bodies containing the hereditary material). Examples of eukaryotic cells are plants, animals, protists, fungi.

<em>Chemiosmosis</em> is the movement of ions across a membrane and it takes place in the mitochondria during cellular respiration and in the chloroplasts during photosynthesis, it is the method which cells use to create ATP (adenosine triphosphate) which is the main molecule used for energy by the cell. Mitochondria generate most of the ATP in cells driven by the proton flow across the inner membrane by a process called chemiosmosis. The free energy from the series of reactions that make up the electron transport chain is used to pump hydrogen ions across the membrane, this energy allows protons (H+) to travel down a proton gradient via chemiosmosis.

<em>Mitochondria </em>are specialized organelles present in the cells of animals, plants and fungi that produce adenosine triphosphate (ATP).

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saveliy_v [14]

A "natural" chemical change would be burning wood, cooking eggs, baking a cake and milk going sour. These changes can't be changed so therefore they are chemical changes.

A natural physical change would be mixing salt or sand with water, melting or boiling water, cutting wood, and shredding paper. The salt and sand can be removed from the water. Hot and cold water are still water. Wood and paper didn't change their composition. All of these examples are reversible.

7 0
3 years ago
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Gold has always been a highly prized metal, and it has been widely used from the beginning of history as a store of value.It doe
Paul [167]

The equation given is incorrect, the correct equation is:

Au(s) + HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)

Answer:

B) It supplies chloride ions to form a complex ion with the oxidized gold.

Explanation:

The equation given is:

Au(s) + HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)

To balance the equation, we need to find the oxidation number (Nox) of the elements, and identify which substance is being oxided and which on is being reduced. Simple elements has Nox = 0, H has Nox = +1, O has Nox = -2. So:

Au(s): Nox Au = 0

HNO₃(aq): Nox H = +1; Nox O = -2, Nox N: +1 +x +3*(-2) = 0 -> x = +5

HCl(aq): Nox H = +1, Nox Cl = -1

HAuCl₄(aq): Nox H = +1, Nox Cl = -1, Nox Au: +1 +x +4*(-1) = 0 -> x = +3

NO₂(g): Nox O = -2; Nox N: x + 2*(-2) = 0 -> x = +4

H₂O(l): Nox H = +1; Nox O = -2

So, Au is being oxidezed from 0 to +3, and N is being reduced from +5 to +4:

ΔNox(Au) = 3

ΔNox(N) = 1

Both of them are single in the compound they are, so it's not necessary to multiply by the coefficient (because is 1). So, the ΔNox must be changed between the compounds:

Au(s) + 3HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)

Now, the balancing must be done by trial, knowing that the elements must be at the same number on both sides of the equation. So, we multiply HCl by 4, and NO₂ and H₂O by 3:

Au(s) + 3HNO₃(aq) + 4HCl(aq) → HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l).

So, we can see that Au is being oxidized, so it's the reducing agent, and HNO₃ ins being reduced, so it's the oxidizing agent. The HCl supplies Cl ions to the complex formed with gold.

4 0
3 years ago
Current is described as
mrs_skeptik [129]
The answer is B the flow of electrons through a substance
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4 years ago
A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
sertanlavr [38]

Answer: The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.947 atm

P_2 = final pressure of gas = 0.987 atm

V_1 = initial volume of gas = 150 ml

V_2 = final volume of gas = 144 ml    

T_1 = initial temperature of gas = 25^0C=(25+273.15)K=298.15K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}

T_2=298.31K=(298.31-273.15)^0C=25.16^0C

The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

4 0
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Kryger [21]

Answer:

C

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