Answer:
22.45g of Fe will be produced
Explanation:
The balanced reaction is:
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)
<em>Where 1 mole of Iron (III) oxide reacts with 2 moles of Iron</em>
<em />
To solve this question we have to find the moles of iron (III) oxide. With these moles and the balanced reaction we can find the moles of iron produced and its mass:
<em>Moles iron (III) oxide -Molar mass: 159.69g/mol-</em>
32.1g Fe₂O₃ * (1mol / 159.69g) = 0.201 moles Fe₂O₃
<em>Moles Iron:</em>
0.201 moles Fe₂O₃ * (2mol Fe / 1mol Fe₂O₃) = 0.402 moles of Fe
<em>Mass Fe -Molar mass: 55.845g/mol-</em>
0.402 moles of Fe * (55.845g/mol) =
<h3>22.45g of Fe will be produced</h3>
The best and correct option is c
Answer: A. The compound CuCl is 500 times less soluble in sea water than it is in pure water.
pure water.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in a equilibrium reaction, the equilibrium will shift in a direction so as to minimize the effect.
Thus when a common ion is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing.
When common ion such as 
from NaCl in sea water is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing i.e. in the left side and thus solubility of CuCl further decreases.
Answer:
<h3>0.2498mol
</h3>
Explanation:
7gN2 x 
=0.2498mol N2
Nitrogen gas has the formula so therefore that means you would have to multiply the mass in the molar by 2. To solve for the number of moles you need to cancel out the grams, you do this by using the molar mass of nitrgoen gas. You get the value on in the denominator from the periodic table (atomic mass of element). The grams will cancel out, leaving you with the number of moles when you divide 7/2(14.01).
Answer:
Rise in charge reduced the size due to rise in attraction between electron and nucleus.
Explanation:
Ion of magnesium is smaller than the atom of magnesium. As the nuclear charge increases, the attraction of electron to the nucleus increases in charged ions form of any element. Due to this increase in charge of magnesium ion, the size of ion reduces
No. of electrons in Mg = 12
No. of proton in Mg = 12
Where as
No. of electrons in Mg2+ = 12
No. of proton in Mg2+ = 10
