Answer:
The induced current is 26.7 mA
Explanation:
Given;
area of the loop, A = 0.078 m²
initial magnetic field, B₁ = 3.8 T
change in the magnetic field strength, dB/dt = 0.24 T/s
The induced emf is calculated as;

The resistance of the loop = 0.7 Ω
The induced current is calculated as;

Not sure but i will say D
Answer:
heat required in pan B is more than pan A
Explanation:
Heat required to raise the temperature of the substance is given by the formula

now we know that both pan contains same volume of water while the mass of pan is different
So here heat required to raise the temperature of water in Pan A is given as


Now similarly for other pan we have


So here by comparing the two equations we can say that heat required in pan B is more than pan A
The answer is 789.25 which you’d subtract 2011.25-122.2 I think sry if I’m wrong