Answer
given,
mass of ball = 5.93 kg
length of the string = 2.35 m
revolve with velocity of 4.75 m/s
acceleration due to gravity = 9.81 m/s² 
T cos θ = mg
T cos θ = 
T cos θ = 58.17 






T² - 56.93T - 3383.75 = 0
T =  93.22 N

θ = 51.39°
 
        
             
        
        
        
Solution :
Given weight of Kathy = 82 kg
Her speed before striking the water,  = 5.50 m/s
 = 5.50 m/s 
Her speed after entering the water,  = 1.1 m/s
= 1.1 m/s 
Time = 1.65 s
Using equation of impulse,

Here, F =  the force , 
        dT =  time interval over which the force is applied for
             = 1.65 s
        dP  = change in momentum 
dP = m x dV
     ![$= m \times [V_f - V_o] $](https://tex.z-dn.net/?f=%24%3D%20m%20%5Ctimes%20%5BV_f%20-%20V_o%5D%20%24)
     = 82 x (1.1 - 5.5)
     = -360 kg
∴ the net force acting will be 


   = 218 N
 
        
             
        
        
        
Answer:
Explanation:
A.
Given:
Vo = 21 m/s
Vf = 0 m/s
Using equation of Motion,
Vf^2 = Vo^2 - 2aS
S = (21^2)/2 × 9.8
= 22.5 m.
B.
Given:
S = 22.5 + 21 mm
= 22.521 m
Vo = 0 m/s
Using the equation of motion, 
S = Vo × t + 1/2 × a × t^2
22.521 = 0 + 1/2 × 9.8 × t^2
t^2 = (2 × 22.521)/9.8
= 4.6
t = 2.14 s
 
        
             
        
        
        
B) using a blood pressure monitor to find a patient's blood pressure.
Hope this helped!