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Vinil7 [7]
3 years ago
7

Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.80×106 N , one at an angle 14.0 ∘ west of north,

and the other at an angle 14.0 ∘ east of north, as they pull the tanker a distance 0.800 km toward the north. Part A What is the total work done by the two tugboats on the supertanker?
Physics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

W = 1,049 10⁹ J

Explanation:

Work is defined by the relation

         W = F. d = F d cos θ

where tea is the angle between the forces and the displacement.

The total work is the sum of the work of each tug.

Tug 1

       W₁ = F d cos θ₁

 

the angle measured from the positive side of the x-axis is

       θ₁ = 14 + 90 = 104º

           

tugboat 2

             W₂ = F d cos θ₂

             θ₂ = 14

we substitute

             W = F d cos θ₁ + F d cos θ₂

             W = F d (cos θ₁ + cos θ₂)

               

let's calculate

             W = 1.80 10⁶  800 (cos 104 + cos 14)

             W = 1,049 10⁹ J

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Answer:

v=0.04m/s\\

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Explanation:

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s=-28.592m\\

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<u>Answer: </u>

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A medicine ball has a mass of 6 kg and is thrown with a speed of 4 m/s. What is its kinetic energy?
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Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 48 \ J}

Given:

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Formula:

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