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Elden [556K]
3 years ago
14

The number of nonoverlapping segments formed by n collinear points is___?​

Mathematics
1 answer:
Fofino [41]3 years ago
5 0

Answer: It will always be n-1.

Step-by-step explanation:

Two examples:

▪-----▪-----▪

3 collinear points --> 2 segments

▪-----▪-----▪-----▪-----▪-----▪

6 collinear points --> 5 segments

It is n MINUS one because the last point does not make another segment.

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The smaller triangle was dilated to form the larger triangle what is the value of x
Sladkaya [172]

Answer:

i think c which is 14

3 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
2 years ago
Chocolate chip cookies have a distribution that is approximately normal with a mean of 24.1 chocolate chips per cookie and a sta
garik1379 [7]
P5

From Z tables and at P5 = 5% = 0.05, Z = -1.645
Therefore,
True value = mean +Z*SD = 24.1+(-1.645*2.1) = 20.6455 Chips per cookie

P95

From Z table and at P95=95%=0.95, Z= 1.645
Therefore,
True value = 24.1 +(1.645*2.1) = 27.5545 Chips per cookie

These values shows the percentages of amount of chips in the cookies. Thus, the more the percentage considered, the more the amount of chips in the cookies. This can be used to control the number of chips in cookies during production.
7 0
3 years ago
Read 2 more answers
X + y = 4
zalisa [80]

Answer:

Well it would come out to 2x-3y=-9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Apples cost a pence each.
Angelina_Jolie [31]

Answer:

\boxed{\sf \ \ 3a \ + \ 5b \ \ }

Step-by-step explanation:

hello

as an apple costs a pence and a banana b pence

3 apples + 5 bananas cost 3*a + 5*b

hope this helps

6 0
3 years ago
Read 2 more answers
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