Control rods is regarded as a substance which can control nuclear reaction and is denoted as option A.
<h3>What is Nuclear reaction?</h3>
This is a type of reaction which involves the nuclei of an atom being split or joined together and is usually accompanied with a great amount of energy emitted in the form of heat.
The two types of nuclear reaction include:
Nuclear fusion involves the collision of two or more nuclei in other form a new atom while nuclear fission involves splitting the atoms to form other products and involves a very high amount of energy and exposure to organisms should be prevented as the radiations can alter DNA.
Control rods are commonly used in nuclear reactors and control the rate of fission in the fuel used. This is therefore the reason why it was chosen as the most appropriate choice.
Read more about Nuclear reaction here brainly.com/question/984564
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Answer: CuSO4>2-butanol> C4H9OH>C2H6>C3H8
Explanation:
Ionic substances are highly soluble in water. CuSO4 is an ionic salt composed of Cu2+ and SO42- ions. These ions are solvated in water hence the salt easily dissolves in the surrounding water molecules. this accounts for the fact that it is the most soluble of the five substances in water. 2-butanol contains the -OH group which interacts with water by hydrogen bonding. This accounts for the miscibility of alkanols with water in all proportions. however, this solubility in water decreases as the alky backbone increases. hence C4H9OH is less soluble in water that 2-butanol. Alkanes are usually not quite soluble in water but again solubility decreases with increase in the alky backbone hence propane is less soluble in water than ethane.
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<span>The reaction of a burning candle gives off heat and is an exothermic reaction. It does not absorb heat because it does not cool down its surroundings as the candle burns. The answer is the reaction of a burning candles gives off heat.</span>
Answer:
-266 kJ
Explanation:
There is some info missing. I think this is the original question.
<em>A mixture of nitrogen and neon gas is expanded from a volume of 53.0 L to a volume of 90.0 L, while the pressure is held constant at 71.0 atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.</em>
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Given data
Initial volume = 53.0 L
Final volume = 90.0 L
Pressure = 71.0 atm
We can find the work (w) associated with the expansion of the gaseous mixture using the following expression.
w = - P × ΔV = - 71.0 atm × (90.0 L - 53.0 L) = -2.63 × 10³ atm . L
w = -2.63 × 10³ atm . L × (101.3 J/ 1 atm . L) = -2.66 × 10⁵ J = -266 kJ
The negative sign means that the system does work on the surroundings.
