Question

I need to find q, r, s, t The function is g(x)=2x^2-8

Answer 1

Answer:

q=0

r=2

s=3

t=-3

Step-by-step explanation:

q represents the value we should get from evaluating d(-8).

$d(x)=-\sqrt{\frac{1}{2}x+4}$

To find d(-8) we use this function here labeled d and replace x with -8:

$d(-8)=-\sqrt{\frac{1}{2}(-8)+4}$

$d(-8)=-\sqrt{-4+4}$

$d(-8)=-\sqrt{0}$

$d(-8)=0$

So q is 0 since d(-8)=0.

r represents the value we should get from evaluating f(0).

$f(x)=\sqrt{\frac{1}{2}x+4}$

To find f(0) we use this function labeled f and repalce x with 0:

$f(0)=\sqrt{\frac{1}{2}(0)+4}$

$f(0)=\sqrt{0+4}$

$f(0)=\sqrt{4}$

$f(0)=2$

So r is 2 since f(0)=2.

s represents the value we should get from evaluating f(10).

$f(x)=\sqrt{\frac{1}{2}x+4}$

To find f(10) we use this function labeled f and replace x with 10:

$f(10)=\sqrt{\frac{1}{2}(10)+4}$

$f(10)=\sqrt{5+4}$

$f(10)=\sqrt{9}$

$f(10)=3$

So s is 3 since f(10)=3.

t represents the value we should get from evaluating d(10).

$d(x)=-\sqrt{\frac{1}{2}x+4}$

To find d(10) we use the function labeled d and replace x with 10:

$d(10)=-\sqrt{\frac{1}{2}(10)+4}$

$d(10)=-\sqrt{5+4}$

$d(10)=-\sqrt{9}$

$d(10)=-3$

So t is -3 since d(10)=-3

q=0

r=2

s=3

t=-3