Answer:
37 mmol of acetate need to add to this solution.
Explanation:
Acetic acid is an weak acid. According to Henderson-Hasselbalch equation for a buffer consist of weak acid (acetic acid) and its conjugate base (acetate)-
![pH=pK_{a}(acetic acid)+log[\frac{mmol of CH_{3}COO^{-}}{mmol of CH_{3}COOH }]](https://tex.z-dn.net/?f=pH%3DpK_%7Ba%7D%28acetic%20acid%29%2Blog%5B%5Cfrac%7Bmmol%20of%20CH_%7B3%7DCOO%5E%7B-%7D%7D%7Bmmol%20of%20CH_%7B3%7DCOOH%20%7D%5D)
Here pH is 5.31,
(acetic acid) is 4.74 and number of mmol of acetic acid is 10 mmol.
Plug in all the values in the above equation:
![5.31=4.74+log[\frac{mmol of CH_{3}COO^{-}}{10}]](https://tex.z-dn.net/?f=5.31%3D4.74%2Blog%5B%5Cfrac%7Bmmol%20of%20CH_%7B3%7DCOO%5E%7B-%7D%7D%7B10%7D%5D)
or, mmol of
= 37
So 37 mmol of acetate need to add to this solution.
Answer:
8
Explanation:
The atomic number refers to the number which identifies the element, which is the proton number.
Answer:48kg of SiO2, 0.5kg of Al2O3, and 1.5kg of B2O3
Will be the final product
Explanation:
I) 96wt% of SiO2 will amount to 96/100*50 = 0.96*50=48kg of SiO2
ii) 1wt% of Al2O3 will amount to 1/100*50 = 0.01*50=0.5kg of Al2O3
III) 3wt% of B2O3 will amount to 3/100*50 = 0.03*50=1.5kg of B2O3..
The overall product form 48+ 0.5+1.5= 50kg
Answer: <em>Acceleration of the ball in the given system is 5 meter per Second Square</em>
<em>The laws of motion are used to determine various aspects of an object in motion</em>.
Explanation:
Applying the first law of motion to calculate acceleration; if formula used in first law is given as 
Here we have a final velocity as 40 meter per second and initial velocity as 20 meter per second and time span is given as 2 second applying the given values in the given equation and finding the value of a