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Agata [3.3K]
3 years ago
11

WHEN A SOCCER PLAYER KICKS A BALL, THE BALL ACCELRATES. EXPLAIN WHAT CAUSES THIS ACCELERATION IN TERMS OF FORCES?

Chemistry
1 answer:
Nana76 [90]3 years ago
5 0

Answer:

When we kick the ball, the force we apply to it causes it to accelerate from a speed of 0 to a speed of dozens of kilometers per hour. When the ball is released from the foot, it begins to decelerate (negative acceleration) due to the force of friction that is exerted upon it (as we observed in the previous example).

Explanation:

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In the process of preparing liquid air for fractional distillation, one fraction will be separated as a solid. What is the chemi
makvit [3.9K]

Answer:

carbon dioxide CO₂

Explanation:

Each gas has a characteristic boiling point. You can separate a random sample of gases by gradually cooling the sample until each component gas liquifies. Some compounds, such as CO₂ never liquify. Instead, they turn directly into solids.

3 0
3 years ago
PLEASEEEEE HELP ME ON QUESTION 8 ASAP!!!!!!!!!!!!!!!!!!! GIVING 20 POINTS
spayn [35]

Answer:

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The reaction of an arrhenius acid with an arrhenius base produces water and
aleksandr82 [10.1K]

Answer: salt

Explanation:

Arrhenius acids are substances which dissociate in water to give H^+ ions.

HCl\rightarrow H^++Cl^-

Arrhenius bases are substances which dissociate in water to give OH^- ions.

NaOH\rightarrow Na^++OH^-

Thus when they combine, they neutralize each other and produce salt and water.

HCl+NaOH\rightarrow NaCl+H_2O

6 0
3 years ago
What do all acids start with?
velikii [3]

Hydrogen

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Acids always dissociate in water, which causes the production of hydrogen ions. Not all necessarily <em>start</em> with hydrogen, but most do and all contain.

5 0
3 years ago
Read 2 more answers
Q.11. Calculate the mass of NaBr needed to prepare a 50.00-mL aqueous solution that would yield the same conductivity as the NaC
klemol [59]

Answer:

The mass of NaBr needed is 0.22969 g.

Explanation:

1 mole of NaBr contains 22.4 dm^3 of NaBr

Therefore, 0.05 dm^3 (50/1000 = 0.05 dm^3) of NaBr = 0.05/22.4 = 0.00223 mol of NaBr

MW of NaBr = 23 + 80 = 103 g/mol

Mass of NaBr = number of moles × MW = 0.00223 × 103 = 0.22969 g

6 0
3 years ago
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