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makkiz [27]
3 years ago
8

What type of reaction does this illustration represent?

Chemistry
1 answer:
natita [175]3 years ago
3 0

Answer:

The answer to your question is A. Decomposition

Explanation:

In the picture, we can observe that there is only one reactant that after the reaction are formed two products.

We observe that this is a decomposition reaction.

It is not a synthesis reaction, this reaction is the opposite of a decomposition reaction.

In a single-replacement and double-replacement reaction, there is an interchange of cations between the reactants, this does not happen in the picture.

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Based on the relative energy of the absorbed electromagnetic radiation, which absorber, a peptide bond or an aromatic side chain
alina1380 [7]

Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.

  • In order to respond to this query, we must decide whether a peptide bond or an aromatic side chain is demonstrating an electronic exited state that is more closely related to the ground state in terms of energy.
  • When our energy is as low as possible, we are in the ground state.
  • What I want to point out is that if we can choose between the two options—peptide bond or aromatic side chain—without knowing the specific reasons, we can immediately rule out two potential answers.
  • Consider what we already know about energy, we have:

                                 E = h x c/λ

  • That indicates that when we have more energy, a wavelength decreases. Lower energy corresponds to higher wavelength.
  • Aromatic side chains absorb between 250 and 290 nm, while peptide bonds do so between 190 and 250 nm.
  • According to our breakdown, we have an electron excited state that is more closely related to the ground state in terms of energy as wavelength increases.

Thus, Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.

To view similar questions about energy, refer to:

brainly.com/question/14483627

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4 0
2 years ago
What would happen if uranium-241 lost 2 protons and 2 neutrons?
kupik [55]
If uranium-241 lost 2 protons and 2 neutrons, then  thorium-237 would be produced. The number beside the element is the mass number which is the sum of protons and neutrons.  If uranium would lose 2 protons and 2 neutrons, then the mass number would decrease by 4 making it 237. Looking in a periodic table, thorium is the element which has a mass number of 237.
5 0
3 years ago
Which of these can be described as a system of stars, gases, dust, and other matter that orbits a common center of gravity?
velikii [3]
It’s c galaxy ((: so yeah
8 0
3 years ago
Read 2 more answers
How do helpful variations increase in a species over time?
Vladimir [108]

Answer:

through natural selection

Explanation:

Natural selection is the driving mechanism of the evolution of species. Organisms can survive more in an environment if they are capable to adapt the changing environmental conditions. After surviving they are also able to pass their modified trait into their future generations (evolution).

Helpful variations accumulate through natural selection, as the organisms that are better adapted to their environment reproduce offspring with the same variations.

7 0
4 years ago
A protein biochemist attempted to determine the amino acid sequence of a decapeptide. Use the results from the trypsin, chymotry
d1i1m1o1n [39]

Answer:

Explanation:

Before I start, let me make one thing clear before we start solving this...I know its says that it will not cleave if it's on the N-side of Proline. HOWEVER, this does not mean the WHOLE N-side...just the immediate N-side Amino Acid. This misunderstanding really screwed me over when I was trying to solve this question.

Ok, so let's start with 10 blanks:

X-X-X-X-X-X-X-X-X-X

Cyanogen bromide cleaves after methionine and leaves a nonapeptide so methionine must be the first one

Met-X-X-X-X-X-X-X-X-X

The information from the trypsin digestion lets us know the first part of the sequence. Since Trypsin cleaves the C side of Lys and Arg, Lys must be the last amino acid

Met-Val-Lys-X-X-X-X-X-X-X

CT3 has Lys, Met, Tyr, and Val and since Met, Val, and Lys are the first three amino acids, Tyr must be the fourth:

Met-Val-Lys-Tyr-X-X-X-X-X-X

Since chymotrypsin cleaves after Tyr and Trp and the sequence is only Thr-Trp, I just put it in next. This is kinda like a "gimme" sequence.

Met-Val-Lys-Tyr-Thr-Trp-X-X-X-X

(we don't have to worry for Trp to be next to Pro since we were told that Ala is the first Amino Acid of CT1's sequence)

All we are missing now is Ala, Arg, Phe, and Pro. Since Ala is the first amino acid of the CT1, that means:

Met-Val-Lys-Tyr-Thr-Trp-Ala-X-X-X

Now this is the part where it can be tricky to explain. This is spot where you can get multiple answers depending on where you look at first or what process of elimination you are using...

There are 4 possible ways to end this sequence...Phe-Arg-Pro, Arg-Phe-Pro, Arg-Pro-Phe, or Phe-Pro-Arg. HOWEVER, Arg-Phe-Pro and Phe-Arg-Pro CANNOT work.

Why?

For Phe-Arg-Pro:

If this was the case then there should have been a CT4: Arg-Pro

For Arg-Phe-Pro:

Then there should have been a T3: Phe-Pro

So your two answers can be:

Met-Val-Lys-Tyr-Thr-Trp-Ala-Phe-Pro-Arg OR Met-Val-Lys-Tyr-Thr-Trp-Ala-Arg-Pro-Phe

3 0
4 years ago
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