Explanation:
to calculate theoratical yield...first we must calculate how much Sucrose moles we have..in order to to do so...we must calculate molar mass of sucrose.
molar mass of sucrose is 342.3 g/mol.
now we can calculate how many sucrose moles we have by dividing the mass with molar mass of sucrose
735g/(342.3g/mol)=2.147mol
theoratically...according to stoichiometry..every 1 mole of sucrose yields 4 moles of ethanol...so...
2.147mole yield 2.147*4mol=8.588mol
now we must calculate weight of that much ethanol..molar mass of ethanol is 46.07 g/mol...
so we can multiple moles by molar mass to obtain the weight 8.588mol*46.07g/mol=395.649g
but we only obtained 310.5g...so percentage we have is
78.47%
if there is trouble with molar mases I used....use what you calculated...
If my explanation is good enough...please mark it as brainliest.thanks
Answer:
8 Toal valence electrons.
Explanation:
For CH4 you have a total of 8 total valence electrons. Drawing the Lewis structure for CH4 (named methane) requires only single bonds. It's one of the easier Lewis structures to draw.
D. A salt e.g NaCl is held by ionic bond
Answer: The IUPAC name of compound is
6-Ethyl-2-Octene.
Explanation:First of all draw a straight chain of 8 carbon atoms.
Make a double bond between carbon number 6 and 7 numbering from left.
Add ethyl group at position 3 starting from left.
The structure sketched is attached below,
According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.
Answer:
Ammonia contains an asymmetrical distribution of electric charge.
Explanation:
Hello there!
In this case, accordingly to the electronegativity difference we can calculate for the N-H bond, and based off our periodic table, which shows an electronegativity of 3.0 and 2.1 for N and H respectively, we obtain:
Which is within the range of polar molecule even the both of them are nonmetals. Thus, choices a and b are firstly discarded; nonetheless, even when they are both nonmetals, two of these elements usually have a nonpolar bond, which means that option C is discarded, and therefore, our answer is ammonia contains an asymmetrical distribution of electric charge.
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