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tester [92]
4 years ago
6

PLEASE FOLLOW THE DIRECTIONS AND SHOW YOUR WORK. IM OFFERING 15PTS (Way more than its worth) AND BRAINLIEST ANSWER. PLEASE HELP

QUICK

Mathematics
1 answer:
Alex4 years ago
3 0
I'll take this challenge since I'm not feeling lazy for once....   x would represent Gavin and y would represent Seiji.  

a.  x+y=425, x-y=25   




b.   I will solve your system using substitution.    
x+y-425, x-y=25  
<span>Step 1: Solve </span>x+y=425 for x
x+y+-y=425+-y (add -y for both sides)
x=-y+425
<span>Step 2: substitute </span>-y+425 for x in x+b=25
x+y=25
<span></span>-y+425-y=25
-2y+425=25 (simplify both sides of the equation)
-2y+425+-425=25+-425 (add -425 to both sides)<span>
</span> -2y=-400
\frac{-2y}{-2} =  \frac{-400}{-2}
y=200
step 3: substitute 200 for y in x=-y+425
x=-y+425
x=-200+425&#10;
x=225
x=225, y= 200




c.   Already answered with the picture that is attached.



d.   Gavin earned 225 dollars while Seiji earned 200 dollars.  

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gregori [183]
Let Jimmy have x silver dollars
then tom have 7+x silver dollars .
from the given condition :
x + x+7 = 71
2x = 71-7
2x=64
x=32
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4 0
4 years ago
Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]

Answer:

-48

Step-by-step explanation:

Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square  of Mx - Ly. In other words

\int\limits_C {L(x,y)} \, dx + M(x,y) \, dy =  \int\limits_0^2\int\limits_0^2 (M_x - L_y ) \, dx \, dy

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,

  • M(x,y) = 4x²y
  • Mx(x,y) = 8xy
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Therefore, the line integral can be computed as follows

\int\limits_C {10y^2x} \, dx + {4x^2y} \,dy = \int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy

Using the linearity of the integral and Barrow's Theorem we have

\int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy = -12 \int\limits_0^2\int\limits_0^2 xy \, dx \, dy = -12 \int\limits_0^2\frac{x^2y}{2} |_{x = 0}^{x=2} \, dy = -12 \int\limits_0^22y \, dy \\= -24 ( \frac{y^2}{2} |_0^2) = -24*2 = -48

As a result, the value of the double integral is -48-

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4 years ago
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Answer:

Step-by-step explanation:

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A box is sitting on the floor. The box was then pulled with a force, Ft. The box did not move. The free-body diagram of the box
WINSTONCH [101]

Answer:

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3 years ago
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Inches of snow Greensboro gets = g
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