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e-lub [12.9K]
3 years ago
6

If 8.77g of potassium iodide (KI) are dissolved in sufficient water to make 4.75L of solution, what is the molarity of the solut

ion
Chemistry
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

0.0111mol/L

Explanation:

M = n/V

We don't know n, but we know that n =mass/Molar mass, so:

n = 8.77g/166.0028 g/mol

n = 0.0528304342mol

M = n/V

M = 0.0528304342mol/ 4.75L

M = 0.111221967mol/L

Round to three sig figs if necessary: 0.0111mol/L

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3 years ago
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How many milliliters of .085 m naoh are required to titrate 25 ml of .072 m hbr to the equivalence point?
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The ML  of 0.85  m NaOH    required   to  titrate  25 ml of  0.72m hbr  to  the  equivalence  point  is calculated  as  follows

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write the  equation  for  reaction

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3 years ago
(image attached)
Naily [24]

Answer:

D) He did not multiply the chlorine and oxygen atoms by the coefficient 4.

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Answer:

This question is incomplete

Explanation:

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Considering the law of conservation of energy which states that energy can neither be created nor destroyed but can be transformed from one form to another. Looking at the example provided earlier for potential energy, a ball in its resting position (having a potential energy) when kicked will have a kinetic energy (which can be calculated with the formula provided earlier), hence

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