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e-lub [12.9K]
3 years ago
6

If 8.77g of potassium iodide (KI) are dissolved in sufficient water to make 4.75L of solution, what is the molarity of the solut

ion
Chemistry
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

0.0111mol/L

Explanation:

M = n/V

We don't know n, but we know that n =mass/Molar mass, so:

n = 8.77g/166.0028 g/mol

n = 0.0528304342mol

M = n/V

M = 0.0528304342mol/ 4.75L

M = 0.111221967mol/L

Round to three sig figs if necessary: 0.0111mol/L

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