The equation for the reaction of magnesium ribbon and hydrochloric acid is
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Answer: The number of moles of produced are, 0.287 moles.
Explanation : Given,
Mass of = 14.9 g
Molar mass of = 32 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 13 mole of react to give 8 moles of
So, 0.466 mole of react to give
mole of
Therefore, the number of moles of produced are, 0.287 moles.
There are three possible Isomers for Molecular Formula C₃H₄. Isomers are;
1) Propyne
2) Propa-1,2-diene
3) Cyclopropene
Structures of all three isomers are given below.
There are no geometrical isomers for given molecular formula because geometrical isomers are formed in compounds containing double bond with at least two bulky groups at both sp² hybridized carbons. In given isomers, propyne does not contain any double bond, Propa-1,2-diene is symmetrical in nature while cyclopropene is a 3-membered ring. And for cycloalkenes there must be other groups attached to ring other than Hydrogen atom, hence cyclopropene does not contain any other group, so it can not show geometrical isomerism.
1) Propyne
2) Propa-1,2-diene
3) Cyclopropene
Structures of all three isomers are given below.
There are no geometrical isomers for given molecular formula because geometrical isomers are formed in compounds containing double bond with at least two bulky groups at both sp² hybridized carbons. In given isomers, propyne does not contain any double bond, Propa-1,2-diene is symmetrical in nature while cyclopropene is a 3-membered ring. And for cycloalkenes there must be other groups attached to ring other than Hydrogen atom, hence cyclopropene does not contain any other group, so it can not show geometrical isomerism.
17.40 sec is the time will take to smell second perfume after diffusion takes place
Acc. to Graham's law of Diffusion
Diffusion of Gas inversely proportional to square root of its Molecular mass.
<u>rb (Perfume B)</u>
ra(perfume A)
= its equation (1)
Give molar mass of Perfume A = 275 g/mol
molar mass of Perfume B= 205g/mol putting value in (1)
»
<em> its eq (2)</em>
» Perfume B will defuse 1:16 times faster than perfume A.
Hence, perfume B will be first smelled by Person.
Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton
Now,, from eq(2) toto
1/1:15 =
ta
Given tb =the smell of Perfume B as it diffuse faster
ta= 1.15 x 15 see
=ta2=17.40 sec
Learn more about diffuse here
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