Question

FIRST TO ANSWER GETS BRAINLIEST! A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form?

Answer 1

Answer:

$n^2+6n+1$

Step-by-step explanation:

AB would be (n) * (2n + 6). We need to distribute the n, so we multiply the n by each term within the parentheses and add those products together:

AB = $n(2n+6)=2n^2+6n$

C is just $n^2-1$ , and we subtract this from $2n^2+6n$:

$2n^2+6n-(n^2-1)=2n^2+6n-n^2+1=n^2+6n+1$

Thus, the answer is $n^2+6n+1$.

Hope this helps!