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marysya [2.9K]
3 years ago
9

Which answer choice correctly solves the division problem and shows the quotient as a simplified fraction?

Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

I need more information to solve this problem

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Please post an provide Simplify 5p^2\5p^3
Rom4ik [11]
( p - 3) or (2p + 1)
5 0
3 years ago
6. A prism has bases that are equilateral triangles with sides lengths of 10 inches and a length of 30 inches.
vova2212 [387]

Answer:

The volume of the prism is 1,299\ in^{3}

Step-by-step explanation:

we know that

The volume of the prism is equal to

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

L=30\ in

<em>Find the area of the base B</em>

The area of a equilateral triangle is equal to

B=\frac{1}{2}(10)^{2} sin(60\°)

B=25\sqrt{3}\ in^{2}

substitute

V=(25\sqrt{3})(30)=1,299\ in^{3}

4 0
3 years ago
The diameter of a circle is 23 inches and the circle has two chords of length 14 inches what is the distance from each chord to
Svetradugi [14.3K]

Answer:

9.12 + 9.12 = 18.24 inches

Step-by-step explanation:

Diameter = 23 inches (given)

Radius = 11.5 inches

2 Chords of length = 14 inches ( You didn't specify if the 14 inches is for both chords or for a single cord. I'll assume it's for two cords 14 and 14inches apart.

To clearly solve this, we'll make some mild assumptions.

Let the perpendicular distance of the chords from the center of the circle to represented as " x and y"

Therefore:

x^2 + 7^2 = 11.5 ^ 2

x^2 + 49 = 132.25

x^2 = 132.25 - 49

x^2 = 83.25

x = √ 83.25

x = 9.12 inches

Since the cords have thesame length (Assumed from the way the question was structured, the distance would still be thesame)

y^2 + 7^2 = 11.5 ^ 2

y^2 + 49 = 132.25

y^2 = 132.25 - 49

y^2 = 83.25

y = √ 83.25

y = 9.12 inches

Therefore, the distance will be :

9.12 + 9.12 = 18.24 inches

Have fun!

6 0
3 years ago
Plz help ASAP number 4 I️ have B and 7 I️ have c plz help with the rest
Veronika [31]

Answer:

5 is interpolation

hope this helps!


4 0
3 years ago
Given sin theta= 6/11 and sec theta &lt; 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

4 0
3 years ago
Read 2 more answers
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