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Bad White [126]
3 years ago
12

30. Justify Reasoning The quotient of two negative integers results in an integer. How does the value of the quotient compare to

the value of the original two integers? Explain.
Mathematics
1 answer:
Ratling [72]3 years ago
6 0
The quotient of 2 negative integers results in an integer.
-4/-2 = 2
the value of the quotient is positive whereas, the value of the original 2 integers are both negative. The reason being, is that when u divide two negatives, u get a positive.
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If 6 × 6 = 36, what value should be subtracted from 36 to find the product of 5 × 6?
Nataly_w [17]

Answer:

The answer to this question is simply 6.

Step-by-step explanation:

You just need to subtract 6 from 36 to get the product of 5x6 which is 30

3 0
3 years ago
Please help. I will give brainliest(:
Tanzania [10]
Distribute the -4. Then combine like terms.

24 - 4(5y - 6z) + 3y - 7z =

= 24 - 20y + 24z + 3y - 7z

= - 20y + 3y + 24z - 7z + 24

= -17y + 17z + 24
7 0
3 years ago
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Suppose f(x)=x^2 and g(x) =7x^2 which statement best compares the graph of g(x) with the graph f(x)
Verizon [17]

Answer:

The graph g(x) is the graph f(x) vertically stretched by a factor of 7.

Step-by-step explanation:

Quadratic Equation: f(x) = a(bx - h)² + k

Since we are modifying the variable <em>a</em>, we are dealing with vertical stretch (a > 1) or vertical shrink (a < 1). Since a > 1 (7 > 1), we are dealing with a vertical stretch by a factor of 7.

8 0
3 years ago
A box with a square base and open top must have a volume of 296352 c m 3 . We wish to find the dimensions of the box that minimi
mestny [16]

Answer:

  • Base Length of 84cm
  • Height of 42 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume, V=x^2h=296352

h=\dfrac{296352}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

A(x,h)=x^2+4xh\\$Substitute h=\dfrac{296352}{x^2}\\A(x)=x^2+4x\left(\dfrac{296352}{x^2}\right)\\A(x)=\dfrac{x^3+1185408}{x}

Step 2: Find the derivative of A(x)

If\:A(x)=\dfrac{x^3+1185408}{x}\\A'(x)=\dfrac{2x^3-1185408}{x^2}

Step 3: Set A'(x)=0 and solve for x

A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84

Step 4: Verify that x=84 is a minimum value

We use the second derivative test

A''(x)=\dfrac{2x^3+2370816}{x^3}\\$When x=84$\\A''(x)=6

Since the second derivative is positive at x=84, then it is a minimum point.

Recall:

h=\dfrac{296352}{x^2}=\dfrac{296352}{84^2}=42

Therefore, the dimensions that minimizes the box surface area are:

  • Base Length of 84cm
  • Height of 42 cm.
5 0
3 years ago
The equation d = d equals StartFraction m Over V EndFraction. can be used to calculate the density, d, of an object with mass, m
Alisiya [41]

Answer:

m/d = V

Step-by-step explanation:

6 0
3 years ago
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