Answer:
(6.8, 1.3)
Step-by-step explanation:
<u>Given</u>:
A(-3, -5), B(11, 4)
<u>Find</u>:
P such that AP/AB = 7/10
<u>Solution</u>:
Using the desired relation, we have ...
(P -A)/(B -A) = 7/10
10(P -A) = 7(B -A) . . . . . multiply by 10(B-A)
10P = 7B +3A . . . . . . . . add 10A to both sides
10P = 7(11, 4) +3(-3, -5) = (77 -9, 28 -15) = (68, 13)
P = (68, 13)/10 = (6.8, 1.3)
The point 7/10 of the way from A to B is (6.8, 1.3).
Answer:
I'm going to say C
it looks the most reasonable to me
Answer:
12.3
Step-by-step explanation:
A^2 + B^2 = C^2
11^2 + 4.5^2 = C^2
132 + 20.25 = C^2
152.25 = C^2
Square root of 152.25 = 12.3
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
Answer:
A and C is true statements
