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gogolik [260]
3 years ago
13

Kelli weighs 440 N, and she is sitting on a playground swing that hangs 0.41 m above the ground. Her mom pulls the swing back an

d releases it when the seat is 1.00 m above the ground. Assume that air resistance is negligible. If Kelli moves through the lowest point at 2.0 m/s, how much work was done on the swing by friction
Physics
1 answer:
kifflom [539]3 years ago
4 0

Answer:

Explanation:

Initial height from the ground = .41 m

Final height = 1m

Height by which Kelli was raised ( h )= .59 m

When she passes through the lowest point , she loses P E

= mgh

= 440 x .59

= 259.6 J

kinetic energy possessed by her

= 1/2 mv²

= .5 x (440/9.8) x 2²

= 89.8 J

Difference of energy is lost due to work by  air friction

work done by  friction = 89.8 - 259.6

= - 169.8 J

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In this problem we know the value of Ax and Ay and we need the angle \alpha.

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Answer:

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