The temperature of the air in the open orang pipe has been altered by 18.73° C
The frequency of an open orang pipe is estimated by using the formula:
Then, the combination of the frequency of the tuning fork and the open orang pipe is:
These combinations of frequency produce 4 beats per sound.
i.e.
When it is altered, the beats first diminish and increase again by 4.
i.e.
If we equate both equations (1) and (2) together, we have:
However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.
Hence;
- when the temperature of the pipe = unknown ???
- the temperature of the open orang pipe = 15
∴
By squaring both sides, we have:
T = 306.726912 - 273
T ≅ 33.73 ° C
∴
The change in temperature ΔT = 33.73° C - 15° C
The change in temperature ΔT = 18.73° C
Learn more about wave frequency here:
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A = distance traveled by steve in north direction by train = 30 miles
B = distance traveled by steve in east direction by train = 25 miles
R = resultant displacement of the steve relative to starting position
using pythagorean theorem
R = √(A² + B²)
inserting the values
R = √(30² + 25²)
R = 39.05 miles
direction : tan⁻¹(B/A) = tan⁻¹(25/30) = 39.8 deg east of north
Answer:
16.96 W
Explanation:
Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).
From the question,
P = (F×d)/t....................... Equation 1
Where P = power, F = force, d = distance, t = time.
Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s
Substitute these values into equation 1
P = (75×42)/186
P = 16.94 W
Hence the average power delivered by the child = 16.96 W
At the tip of either of the magnets poles
Answer:
D. 0.1
Explanation:
Using transformer equation,
N2/N1 = I1/I2................... Equation 1
Where N2 = secondary coil, N1 = primary coil, I1 = input current, I2 = output current.
make I2 the subject of the equation
I2 = I1/(N2/N1)............ Equation 2
From equation 2 above, For the output current of the secondary coil to be 10 times the input current, N2/N1 = 0.1
Hence the right option is D. 0.1
