All categories

3 years ago

A force =(16.8N/s)t is applied to an object of m=45.0kg. Ignoring friction, how far does the object travel from rest in 5.00s?

Physics

1 answer:

kirza4 [7]3 years ago

6 0

Answer:

Explanation:

a = F/m = 16.8t/45 = 0.373*t

v = ∫a*dt = ∫(0.373*t)dt = 0.1865*t²

x = ∫v*dt = 0.1865∫(t²)dt = 0.062*t³

For t = 5.0 sec,

x = 0.062*(5)^3 = 7.75 m

You might be interested in

A planet orbits the Sun<br>every 4.5 years. uniform or non uniform velocity?

Charra [1.4K]

Non uniform velocity

5 0

3 years ago

in an automobile crash, a vehicle was stopped at a red light is rear-ended by another vehicle. The vehicles have the same mass.

Masja [62]

8 m/s

Explanation:

Using conservation of momentum :-

$m1u1 + m2v1 = m1u2 + m2v2$

Where:

m1 = Mass of first vehicle

m2 = Mass of second vehicle

u1 = initial speed of first vehicle

v1 = initial speed of second vehicle

u2 = Final speed of first vehicle

v1 = Final speed of second vehicle

From the received informations:

$m1 = m2$

$v1 = 0$

$v2 = u2 = 4 \frac{m}{s}$

$m1u1 + 0 = 4m1 + 4m1$

Now divide both sides by m1 :-

$u1 = 4 + 4$

$u1 = 8m/s$

Therefore, final answer is 8 m/s

4 0

3 years ago

What is the role of the midbrain, and which part of the midbrain is important for arousing the forebrain?

Rainbow [258]

Answer:

The fore-brain consists of the cerebrum, thalamus, and hypothalamus. Mid-brain relays information between fore-brain and hind-brain. Mid-brain plays important role in developing motor functions like eye movement, auditory functions and visual processing. The crus cerebri connects the cerebral hemispheres to the cerebellum, contains a portion having a network of neurons that is responsible for arousal and alertness.

6 0

3 years ago

What do you understand by the term intensity of sound

tensa zangetsu [6.8K]

Answer:

It means how loud or how soft an object vibrates.

Explanation:

6 0

3 years ago

Two workers are sliding 350 kgkg crate across the floor. One worker pushes forward on the crate with a force of 390 NN while the

svetoff [14.1K]

Answer:

$\mu_k=0.18$

Explanation:

First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:

$x: T+F-f_k=0\\\\y:N-mg=0$

Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.

Since $f_k=\mu_k N$ and $N=mg$ , we can rewrite the first equation as:

$T+F-\mu_k mg=0$

Now, we solve for $\mu_k$ and calculate it:

$\mu_k=\frac{T+F}{mg}\\ \\\mu_k =\frac{220N+390N}{(350kg)(9.8m/s^{2})} =0.18$

This means that the crate's coefficient of kinetic friction on the floor is 0.18.

6 0

4 years ago