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lesantik [10]
3 years ago
5

A force =(16.8N/s)t is applied to an object of m=45.0kg. Ignoring friction, how far does the object travel from rest in 5.00s?

Physics
1 answer:
kirza4 [7]3 years ago
6 0

Answer:

Explanation:

a = F/m = 16.8t/45 = 0.373*t

v = ∫a*dt = ∫(0.373*t)dt = 0.1865*t²

x = ∫v*dt = 0.1865∫(t²)dt = 0.062*t³

For t = 5.0 sec,

x = 0.062*(5)^3 = 7.75 m

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The ideal mechanical advantage of a lever (IMA) is given by:

IMA=\frac{Le}{Lr}

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4 0
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You are preparing a performance review and have the following measurement at hand: pv = 300; ac = 200; and ev = 250. what is cpi
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CPI of the project is 1.25 so the correct answer is B

EV / AC is the formula used to calculate CPI. Here, 250 divided by 200 equals 1.25.The worth of the work that has been finished thus far in comparison to the budget is referred to as earned value.A. Schedule performance index equals (EV / PV) and schedule variance equals (EV - PV).The CPI is regarded as the most important EVM metric. It gauges the project work's cost effectiveness as of the measurement date.

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3 0
2 years ago
The driver of a car traveling at 30.5 m/s slams on the brakes so that the car undergoes a constant acceleration, skidding to a c
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3 years ago
Joe is measuring the time it takes for a ball to roll down a ramp. In this experiment Joe takes the measurement 5 times and gets
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 Step by step solution :

standard deviation is given by :

\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}

where, \sigma is standard deviation

\bar{x} is mean of given data

n is number of observations

From the above data, \bar{x}=24.88

Now, if x=24.8, then (x-\bar{x})^2=0.0064

If  x=23.9, then (x-\bar{x})^2=0.9604

if x=26.1, then (x-\bar{x})^2=1.4884

If x=25.1, then (x-\bar{x})^2=0.0484

If x=24.5, then (x-\bar{x})^2=0.1444

so, \sum (x-\bar{x})^2 =\frac{0.0064+0.9604+1.4884+0.0484+0.1444}{5}

\sum (x-\bar{x})^2 =2.648

\sqrt{\sum \frac{(x-\bar{x})^2}{n}}

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No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.

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