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3 years ago

What happens to the compass needle as you move the compas around the magnet?

Physics

1 answer:

Ugo [173]3 years ago

4 0

Answer:

When you moved the compass near a bar magnet, the needle pointed toward the magnet's magnetic field and not toward the north.

Explanation:

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What force must be applied to the end of a rod along the x-axis of length 2.25 m in order to produce a torque on the rod about t

4vir4ik [10]

Answer:

<h2>4.9N approx.</h2>

Explanation:

Step one:

given data

length of rod r= 2.25m

Required torque = 11 Nm

Required

The force needed to produce a torque of 11Nm

Step two:

<em>"By definition, Torque is the twisting force that tends to cause rotation. </em>

<em>The point where the object rotates is known as the axis of rotation."</em>

Mathematically,

$\tau = rF\sin\theta$

$\tau$ = torque

r = radius

F = force

$\theta$ = angle between F and the lever arm

in this case is zero

$\tau = rF\\\\F=\tau/r$

substituting we have

F=11/2.25

F=4.88N

F=4.9N approx.

7 0

2 years ago

What is Albert Einstein’s contribution to the understanding of nuclear energy?

Phoenix [80]

Einstein's equations showed that matter could be converted into energy; and vice-versa
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7 0

2 years ago

Read 2 more answers

A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 3.0 km/h

Yuki888 [10]

Answer:

The magnitude of F₁ is 3.7 times of F₂

Explanation:

Given that,

Time = 10 sec

Speed = 3.0 km/h

Speed of second tugboat = 11 km/h

We need to calculate the speed

$v_{1}=\dfrac{3.0\times10^{3}}{3600}$

$v_{1}=0.833\ m/s$

The force F₁is constant acceleration is also a constant.

$F_{1}=ma_{1}$

We need to calculate the acceleration

Using formula of acceleration

$a_{1}=\dfrac{v}{t}$

$a_{1}=\dfrac{0.833}{10}$

$a_{1}=0.083\ m/s^2$

Similarly,

$F_{2}=ma_{2}$

For total force,

$F_{3}=F_{2}+F_{1}$

$ma_{3}=ma_{2}+ma_{1}$

The speed of second tugboat is

$v=\dfrac{11\times10^{3}}{3600}$

$v=3.05\ m/s$

We need to calculate total acceleration

$a_{3}=\dfrac{v}{t}$

$a_{3}=\dfrac{3.05}{10}$

$a_{3}=0.305\ m/s^2$

We need to calculate the acceleration a₂

$0.305=a_{2}+0.083$

$a_{2}=0.305-0.083$

$a_{2}=0.222\ m/s^2$

We need to calculate the factor of F₁ and F₂

Dividing force F₁ by F₂

$\dfrac{F_{1}}{F_{2}}=\dfrac{m\times0.83}{m\times0.22}$

$\dfrac{F_{1}}{F_{2}}=3.7$

$F_{1}=3.7F_{2}$

Hence, The magnitude of F₁ is 3.7 times of F₂

3 0

3 years ago

Which example best represents translational kenetic energy

Mila [183]

Answer:

an apple falling off a tree

Explanation:

5 0

2 years ago

At standard temperature and pressure, carbon dioxide has a density of 1.98 kg/m3. What volume does 1.70 kg of carbon dioxide occ

nikitadnepr [17]

Answer:

<h2>volume= 0.85m^3</h2>

Explanation:

<em>The density of a substance is defined as the mass per unit volume of the substance, the unit is in kg/m^3 and it is represented by the greek letter rho</em>

Step one:

given data

we are told that the density of Co2= 1.98 kg/m3

and the mass of Co2 is= 1.70 kg

we know the relation between mass, volume and density is

$density=mass/volume$

make volume subject of formula we have

$volume=mass/density$

substitute we have

$volume=1.7/1.98\\\\volume= 0.85m^3$

8 0

3 years ago