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Harlamova29_29 [7]
3 years ago
7

What happens to the compass needle as you move the compas around the magnet?

Physics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

When you moved the compass near a bar magnet, the needle pointed toward the magnet's magnetic field and not toward the north.

Explanation:

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Making the material you are trying to memorize personally meaningful to you is called the ____________.
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Answer:

Making the material you are trying to memorize personally meaningful to you is called the?

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8 0
2 years ago
How do scientist know that seismic waves can be either compressional or transverse
nasty-shy [4]
Hey there! 

<span>Scientists know that seismic waves can be either compressional or transverse because there are horizontal and vertical movements during an earthquake. Horizontal movements are compressional while vertical movements are transverse. 

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8 0
3 years ago
If the mass of a material is 41 grams and the volume of the material is 5 cm^3, what would the density of the material be? answe
Mila [183]
Density can be calculated using the following rule:
Density = mass/volume

We are given that:
mass = 41 grams
volume = 5 cm^3

Substitute with the givens in the above equation to get the density as follows:
Density = 41/5 = 8.2 g/cm^3

Based on the above calculations:
answer : 8.2
units : g/cm^3
6 0
2 years ago
Read 2 more answers
A point charge of 6.0 nC is placed at the center of a hollow spherical conductor (inner radius = 1.0 cm, outer radius = 2.0 cm)
egoroff_w [7]

Explanation:

The given data is as follows.

             q = 6.0 nC = 6 \times 10^{-9} C

         inner radius (r) = 1.0 cm = 0.01 m   (as 1 cm = 100 m)

So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.

Formula to calculate the charge density is as follows.

            \sigma = \frac{q_{in}}{A} .......... (1)

Since, area of the sphere is as follows.

               A = 4 \pi r^{2} ........... (2)

Hence, substituting equation (2) in equation (1) as follows.

      \sigma = \frac{q_{in}}{4 \pi r^{2}}

                   = \frac{6 \times 10^{-9} C}{4 \times 3.14 \times (0.01)^{2}}            

                   = 0.477 \times 10^{-5}

or,               = 4.77 \mu C/m^{2}

Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 \mu C/m^{2}.

5 0
2 years ago
The ball X has a known position at 3 different times, each 1 second apart. The positions of the ball are (1.8,2.2)m, (4.4,4.8)m,
Mandarinka [93]

Answer:

Explanation:

From the position coordinates given , it appears that the ball moves simultaneously along x and y direction.

Displacement along x direction in one second = 4.4 - 1.8 = 2.6 m

So velocity along x direction V_x = \frac{2.6}{s}

Similarly velocity along y direction V_y(1) =  \frac{2.6}{s}

In the next phase velocity changes both in x and y direction.

velocity in x - direction V_x(2) = [tex]\frac{2}{s}[/tex

Velocity in Y- direction V_y(2) = [tex]\frac{3.1}{s}[/tex

Acceleration in x direction = change of velocity in x direction

= ( 2 - 2.6 ) = -.6 m s⁻²

Acceleration in y direction = ( 3.1 - 2.6 ) = 0.5 m s⁻²

Total acceleration =\sqrt{( -.6 )² + ( .5 )²}

= .78 ms⁻²

6 0
3 years ago
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