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Harlamova29_29 [7]
3 years ago
7

What happens to the compass needle as you move the compas around the magnet?

Physics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

When you moved the compass near a bar magnet, the needle pointed toward the magnet's magnetic field and not toward the north.

Explanation:

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Vlad [161]

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The second one a part of it heats up Earth's land and water equally.

Explanation:

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5 0
4 years ago
7) If the mass of an object is 694 g, find the mass of rider 1 if rider 2 = 600g rider 3 = 90 (Subtract the smaller numbers from
icang [17]

The mass of the rider 1 is 4 g.

<h3>The use of a rider in mass measurement</h3>

Rider is a metallic wire piece which is of certain mass and can be bent . It can move the beam of the Paul Bunge Balance.

The riders are the sliding pointers positioned on top of the beams to show the pan and beam weight in grams.

<h3>Mass of the rider 1</h3>

The mass of the rider 1 is obtained by subtracting mass of riders as show below.

mass of rider 1 = mass of object - (mass of rider 2 + mass of rider 3)

mass of rider 1 = 694 g  - (600 g + 90 g)

mass of rider 1 = 694 g - 690 g

mass of rider 1 = 4 g

Thus, the mass of the rider 1 is 4 g.

Learn more about use of riders in mass measurement here: brainly.com/question/1747339

#SPJ1

8 0
2 years ago
The weight of a girl on the Earth is 340 N, what is her mass on Earth?(g= 10Nkg-1)​
kirill [66]

Answer:

34 kg is the answer to the question

4 0
3 years ago
A point charge gives rise to an electric field with magnitude 2 N/C at a distance of 4 m. If the distance is increased to 20 m,
worty [1.4K]

Answer:

0.08 N/C

Explanation:

Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,

E = Kq/r².............................. Equation 1

Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.

making q the subject of the equation,

q = Er²/k............................... Equation 2

Given: E = 2 N/C, r = 4 m,

Substitute into equation 2

q = 2(4)²/k

q = 32/k C.

When r is increased to 20 m,

E = k(32/k)/20²

E = 32/400

E = 0.08 N/C.

Hence the electric Field = 0.08 N/C

5 0
4 years ago
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