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3 years ago

Why do we never notice quantization?

Physics

1 answer:

jarptica [38.1K]3 years ago

7 0

Answer:

Explanation:

quantization of energy is only seen in atoms

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Whenever Dylan walks into his room, his roommate loudly blows an air horn, which startles Dylan. Dylan doesn't think this is fun

Sav [38]

Answer:

stimuli

Explanation:

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2 years ago

Speed is different from velocity because

shtirl [24]

Answer:

A. velocity has a direction .. .

with magnitude too but speed has only magnitude

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2 years ago

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If you have a density of 100kg/L and a mass of 1000 units, tell me the following: second what is the volume

adell [148]

Answer:

volume is 0.1 L

Explanation:

you can use the equation density=mass/volume

100 = 1000 / v

divide by 1000 on both sides

0.1 = v

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2 years ago

When a car suddenly stops at a red light, a book lying on the car seat slides forward. Why does the book continue to move forwar

mr_godi [17]

Answer:

<u>The book's inertia causes it to continue moving.</u>

Inertia can be defined as the tendency of an object such as a book to continue in its state of motion or remain at rest, unless it is acted upon by an external force.

Explanation:

Does this help you???

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1 year ago

How would the speed of Earth's orbit around the sun change if Earth's distance from the sun

gayaneshka [121]

If Earth’s distance from the sun increased by 4 times then the speed of Earth’s orbit around the sun would decrease by a factor of 2.

Answer: Option 3

<u>Explanation:</u>

From Newton’s second law of motion, it is known that any kind of external force acting on an object will be equal to object’s mass and acceleration exerted on the object. So in this case, the gravitational force between Earth and Sun will be equal to the mass (M) and acceleration exerted on Earth.

$\text {Gravitational force}=\text {M} \times \text {Acceleration of Earth around the orbit}$

It is known that,

$\text {Acceleration in orbital motion}=\frac{\left(\text {velocity at which the Earth rotates)}^{2}\right.}{\text { Distance of Earth from the Sun}}$

Thus, substituting this, we get,

$\text {Gravitational force}=\frac{\text {M} \times\left(\text {velocity at which the Earth rotates)}^{2}\right.}{\text { Distance of Earth from the sun}}$

Also, we know,

$\text {Gravitational force}=\frac{G \times M \text { of sun } \times \text {M of Earth}}{(\text {Distance of Earth from the Sun})^{2}}$

Then, comparing both the equation, we get the orbital velocity as,

$\text { Orbital velocity } v=\sqrt{\frac{G \times M \text { of Sun }}{\text { Distance of Earth from the Sun }}}=\sqrt{\frac{G M}{r}}$

So, here G is gravitational constant, M is the mass of Sun and r is the distance of separation of Earth from Sun.

If the distance of Earth from Sun increases by 4 times so r’ will be 4r. Thus the new orbital velocity v’ will be

$v^{\prime}=\sqrt{\frac{G M}{r^{\prime}}}=\sqrt{\frac{G M}{4 r}}=\frac{1}{2} \sqrt{\frac{G M}{r}}$

So,

$v^{\prime}=\frac{1}{2} v$

Thus, the orbital speed will be decreased by a factor of 2 when the distance of Earth from the Sun increased by 4 times.

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3 years ago