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Irina-Kira [14]
3 years ago
6

How does a physicist answer a scientific question?

Physics
1 answer:
egoroff_w [7]3 years ago
6 0

Answer:

He does an experment.

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A _____ has a definite ratio of components
user100 [1]
A compound has a definite ratio of components
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4 years ago
Read 2 more answers
Anyone know this stuff?
Varvara68 [4.7K]
Yes, I do! Vectors have a direction linked to them and scalars don’t.
6 0
3 years ago
What must change in order for electromagnetic induction to occur in a wire coil?.
mihalych1998 [28]

Answer:

The magnetic field through the coil must change.

Explanation:

4 0
2 years ago
A ball is thrown straight up into the air with an initial velocity of 50 ft/sec. The height h(t) of the ball after t seconds is
Scrat [10]

Answer:

The average velocity for the time period beginning when t=1 and lasting 0.1 seconds = 16.40 ft/s.

Explanation:

Given that the height of the ball at time t is

\rm h(t) = (50 t-16t^2)\ ft.

The average velocity of an object is defined as the total displacement covered by the particle divided by the total time taken in covering that displacement.

If \rm h_1,\ h_2 are the heights of the ball at time \rm t_1 and \rm t_2, then the total displacement covered by the ball from time \rm t_2 to \rm t_1 is \rm h_2-h_1.

Thus, the average velocity of the ball for the time interval \rm t_2-t_1  is given by

\rm v_{av}=\dfrac{h_2-h_1}{t_2-t_1}.

For the time interval, beginning when t = 1 second and lasting 0.1 seconds,

\rm t_1=1\ sec.\\t_2 = 1\sec + 0.1\ sec = 1.1\ sec.\\\\h_1=50\times 1-16\times 1^2=34\ ft.\\h_2=50\times 1.1-16\times 1.1^2=35.64\\\\Therefore,\\\\v_{av} = \dfrac{35.64-34}{1.1-1}=16.40\ ft/s.

7 0
3 years ago
A worker uses a cart to move a load of bricks weighing 680 N a distance of 10 m across a parking lot. If the worker pushes the c
Nonamiya [84]
The equation for calculating the Work is very simple that is Work=Force x Displacement. We have a Force given as 209N and displacement = 10 meter.
Putting these values directly in the formula gives us Work = 209N x 10m
Work = 2090 Joule.

The weight of the bricks is not needed hear. 
5 0
4 years ago
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