Answer:
Explanation:
The problem tell us that the temperature as function of time in downtown mathville is given by:
The average temperature over a given interval can be calculated as:
Where:
So, the initial temperature in this case, would be the temperature at noon, and the final temperature would be the temperature at midnight:
Therefore:
Hence, the average temperature between noon and midnight is:
Answer:
49.85 V
Explanation:
u = 0, s = 5.62 cm, t = 1.15 x 10^-6 s
Let the electric field is E and voltage is V.
Use second equation of motion
s = ut + 1/2 a t^2
5.62 x 10^-2 = 0 + 0.5 a x (1.15 x 10^-6)^2
a = 8.5 x 10^10 m/s^2
m x a = q x E
E = m x a / q
E = (1.67 x 10^-27 x 8.5 x 10^10) / (1.6 x 10^-19)
E = 887.19 V/m
V = E x s
V = 887.19 x 5.62 x 10^-2 = 49.85 V
Answer:
Mass=3,height=50 and time=15,g=10,P=?
P=mgh/t....which is 3×10×50=1500/15=100Watts
Answer:
The correct answer should be high amplitude : )
Explanation:
A high energy wave is characterized by a high amplitude, a low energy wave is characterized by a low amplitud
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