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3 years ago

6

A magnet school program was set up to bring in students from all over the city. With the first 112 students, the magnet program

had 50% from the south side of town, 12.5% from the north side l, and 37.5% from the east side. If 6 more student from the north side and 2 students from the west side side enrolled in the program, what would be the percentage of students from the north side of the city in the program now?

1 answer:

Galina-37 [17]3 years ago

4 0

Answer

Find out the percentage of students from the north side of the city in the program .

To prove

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ value}$

As given

A magnet school program was set up to bring in students from all over the city. With the first 112 students .

the magnet program had 50% from the south side of town, 12.5% from the north side l, and 37.5% from the east side.

12 .5 % is written in the decimal form.

$= \frac{12.5}{100}$

= 0.125

North side student be = 0.125 × 112

= 14

As given

If 6 more student from the north side and 2 students from the west side side enrolled in the program .

than north side student becomes = 14 + 6

= 20

Total number of student becomes = 112 + 6 + 2

= 120

put in the above formula

$Percentage =\frac{20\times100}{120}$

$Percentage =\frac{2000}{120}$

= 16.66% (approx)

Therefore 16.66% (approx) students from the north side of the city in the program .

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Answer:

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Step-by-step explanation:

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Now,

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Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

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Or, 19 × ( 2 y + 49 ) = y² + 49 y

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3 years ago

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$AB = 2\cdot BC$

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Where:

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Then, we expand and simplify the expression above:

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