Question

URGENT! WILL GIVE BRAINLIEST!!

Answer 1

Answer:

Option C) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Step-by-step explanation:

Given infinite sequence is ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Option B) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Now verify  $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is true for the given infinite sequence

That is put n=1,2,3,.. in the above function

$a_{n}=m-b+m(n-1)$

When n=1,  $a_{1}=m-b+m(1-1)$

$=m-b+0$

$a_{1}=m-b\neq m+b$

When n=2,  $a_{2}=m-b+m(2-1)$

$=m-b+m$

$a_{2}=2m-b\neq 2m+b$

When n=3,  $a_{3}=m-b+m(3-1)$

$=m-b+2m$

$a_{3}=3m-b\neq 3m+b$

and so on.

Therfore $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Therefore option C) is correct