All categories

3 years ago

How do you convert improper fractions to proper fractions

Mathematics

2 answers:

Jobisdone [24]3 years ago

5 0

Answer:

Step- for example, 27/6. The fraction bar means you need to divide 27 by 6.

Divide 27 by 6. The answer is 4, with a remainder of 3. Use the answer as the whole number part of the mixed number, and place the remainder over the original denominator: 4 3/6.

lozanna [386]3 years ago

5 0

You use “top in bottom out” method. Take the improper fraction, let’s use 49/5. First, concert the improper fraction into a decimal by dividing the numerator by the denominator. You should get 9.8. Convert the 9.8 into a mixed number by placing the number to the right of the decimal over 10. Then reduce your fraction. You should get 9 4/5 and that’s your answer

You might be interested in

Help help help please

myrzilka [38]

100035 because the numbers are all even and i am in first grade so yeah

7 0

2 years ago

A farmer owns a 100 acre farm and plans to plant at most three crops. The seed for crops A,B, and C costs $40, $20, and $30 per

aev [14]

Answer:

The number of acre per crop for maximum profit is;

Crop A = 0 acres

Crop B = 60 acres

Crop C = 40 acres

Profit, P = $26,000

Step-by-step explanation:

We plant A in X acres

B in Y acres and

C in Z acres

Therefore, X + Y + Z ≤ 100

we work A for 1·X workdays

B for 2·Y workdays and

C for 1·Z workdays

Where X + 2·Y + Z ≤ 160

$40·X for crop A

$20·Y for crop B and

$30·Z for crop C is spent whereby

$40·X + $20·Y + $30·Z ≤ $3200

The farmer makes

$100·X from crop A

$300·Y from crop B and

$200·Z from crop C

P = $100·X + $300·Y + $200·Z

Therefore, we have three equations with three unknowns solving the equations simultaneously, we have

X + Y + Z = 100....................................................(1)

X + 2·Y + Z = 160.................................................(2)

$40·X + $20·Y + $30·Z = $3200....................(3)

By subtracting equation (1) from (2) gives Y = 60 acres

Multiplying equation (1) by 40 and subtracting from (3) we have Z = -40

and therefore, Y = 80

If he plants only B the farmer has 2 work day per acre and since there is a max of 160 days, he can only plant on 80 acres, therefore, total profit = $300 × 80 = $24,000

Comparing the profit per acre to the seed cost we have Profit for seed A = $100 while cost = $40 per acre,

If we remove seed A we have

Y + Z = 100....................................................(4)

2·Y + Z = 160.................................................(5)

$40·X + $20·Y + $30·Z = $3200....................(3)

Solving equation (4) and (5), we have Y = 60 acres and Z = 40 acres

Therefore, the profit becomes

$300 × 60 + $200 × 40 = $26,000.

3 0

3 years ago

Which equation best represents this situation?

Harlamova29_29 [7]

Hello!

We have the difference between 30 and x(our unknown value) is equal to 17; so we just simply set it up that way. Always think of x or any variable(like in your question they use p, it can be anything u want, it’s simply a representation of an unknown value we are trying to find)as your unknown and what operation they are implying as in this case it’s subtraction as they want the difference between 30 and x.

So the answer is a. 30-p=17

Hope this helped and any questions please just ask. Thank you!

7 0

3 years ago

A sample of size 126 will be drawn from a population with mean 26 and standard deviation 3. Use the TI-84 calculator.

GenaCL600 [577]

Answer:

1. The probability that x will be more than 25 is 0.6305.

2. The 55th percentile is 26.38.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 26 and standard deviation 3.

This means that $\mu = 26, \sigma = 3$