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Juliette [100K]
3 years ago
9

Question is above pls helpA)2B)3C)4D)5​

Chemistry
1 answer:
zvonat [6]3 years ago
7 0

Answer:

5 will come in blank

4KMnO₄ ----------> 2K₂O + 4MnO + 5O₂

Explanation:

Reaction:

4KMnO₄ ----------> 2K₂O + 4MnO + ____O₂

this reaction is the dissociation reaction in which KMnO₄ is break down into its component.

KMnO₄ upon dissociation gives Potassium oxide, manganese oxide and liberate oxygen

Balance Chemical Equation:

A balanced chemical equation is that in which the the number of the reactant atoms equal to the number of the product atom.

For example if the oxygen at the reactant side is 4, the number of oxygen should be 4 on the product side.

So for this purpose  we have to balnce the reaction and number of atoms on each side of the arrow

if we see the given Equation

Numbers of atom on reactant Side:

K = 4

Mn = 4

O = 16

Numbers of atom on reactant Side:

K = 4

Mn = 4

O = 6 instead of blank oxygen molecule

so from the above data we have 10 oxygen less.

If we put the 5 in the blank then we will have 10 oxygen and equation will be balanced

So the balanced Equation will be

4KMnO₄ ----------> 2K₂O + 4MnO + 5O₂

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How many total electrons can enter the set of 3p orbitals?<br> a. 3<br> b. 10<br> c. 2<br> d. 6
Sliva [168]

Answer:

For n=3 and l=1=p

It is 3p-orbital.

Magnetic quantum number m

l

have values from -l to +l and total of 2l+1 values.

Forl=1, m

l

values are:

m

l

=−1,0,1 for l=1; total m

l

values =3= Number of orbitals

Each orbital can occupy maximum of two electron

Number of electrons =2×3=6

Thus 6 electrons will show same quantum number values of n=3 and l=1.

Number of elements with last electron in 3p orbitals = 6

5 0
3 years ago
Calculate the change in pH when 71.0 mL of a 0.760 M solution of NaOH is added to 1.00 L of a solution that is 1.0O M in sodium
Eddi Din [679]

Explanation:

It is known that pK_{a} value of acetic acid is 4.74. And, relation between pH and pK_{a} is as follows.

                    pH = pK_{a} + log \frac{[CH_{3}COOH]}{[CH_{3}COONa]}

                          = 4.74 + log \frac{1.00}{1.00}

So, number of moles of NaOH = Volume × Molarity

                                                   = 71.0 ml × 0.760 M

                                                    = 0.05396 mol

Also, moles of  CH_{3}COOH = moles of CH_{3}COONa

                                          = Molarity × Volume

                                          = 1.00 M × 1.00 L

                                          = 1.00 mol

Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

            CH_{3}COONa + NaOH \rightarrow CH_{3}COOH

Initial :    1.00 mol                                  1.00 mol

NaoH addition:               0.05396 mol

Equilibrium : (1 - 0.05396 mol)    0           (1.00 + 0.05396 mol)

                    = 0.94604 mol                       = 1.05396 mol

As, pH = pK_{a} + log \frac{[CH_{3}COONa]}{[CH_{3}COOH]}

               = 4.74 +  log \frac{0.94604}{1.05396}

               = 4.69

Therefore, change in pH will be calculated as follows.

                         pH = 4.74 - 4.69

                               = 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

8 0
3 years ago
Which has the larger radius, F or F− ?
vlabodo [156]

Answer is B-  F has a smaller radius than F− because an additional electron causes greater repulsion in F− is the correct choice and the nuclear charge the radius of the anion increases.

Explanation: I hoped that helped!

6 0
3 years ago
Pls help me <br><br> What is the mass in grams of 2.64 mol of sulfur dioxide, SO2?
notsponge [240]

Answer: The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles SO2, or 64.0638 grams.

Hope it helps.

8 0
3 years ago
A solution is made by mixing 34.5 g of sugar with 75.0 g of water. What is the mass percent of sugar in this solution?
lubasha [3.4K]

the mass percent of sugar in this solution is 46%.

Answer:

Solution given:

mass of solute=34.5g

mass of solvent=75g

mass percent=\frac{mass\:of\:solute}{mass\:of \:solvent}*100\%

=\bold{\frac{34.5}{75.0}*100\%=46\%}

5 0
3 years ago
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