I qould say the answer is b. 59.
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
</span>
</span>
237/4 = 59.25
Hope that helps
WHAT IS 1+100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000=
Keith_Richards [23]
Answer:
100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,001
Step-by-step explanation:
Hope this helps!:)
Answer:
answer is 1 answer is 4-5 = 1 is 3-6 answer is only 3
