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sleet_krkn [62]
3 years ago
10

I'm completely lost, I need help solving this

Mathematics
1 answer:
olasank [31]3 years ago
6 0
Follow the operation of PEMDAS
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Write the equation of the line that is parallel to
Kruka [31]

Answer:

y = -x + 2

Step-by-step explanation:

Lines that are parallel have the same slope but different

y-intercepts.

So the slope of the parallel line is -x

We can input the x and y points given to solve for the new y-intercept

  • y = -x + b
  • 8 = -(-6) + b
  • 8 = 6 + b
  • b = 2

The new line is y = -x + 2. Since these two lines are the same, they are coinciding lines.

-Chetan K

4 0
2 years ago
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Tom made $450 selling CDs last month. That total increased to $513 this month. What was the percent increase? (pls answer)
svetoff [14.1K]

Answer:

14%

Step-by-step explanation:

7 0
3 years ago
Write an equation that represents the remaining number of meals y, after x number of hours. (❍ᴥ❍ʋ)help please
7nadin3 [17]
Y = 600 - 55x is the equation
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2 years ago
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What is the vertex form of the parabola whose standard form equation is y=5x^2-30x+49
agasfer [191]

Answer:

The vertex is (3,4)

Step-by-step explanation:

To convert a quadratic from  

y = a x 2 + b x + c

form to vertex form,

y = a ( x − h ) 2 + k , you use the process of completing the square.

First, we must isolate the  x

terms:

y − 49 = 5 x 2 − 30 x + 49 − 49

y − 49 = 5 x 2 − 30 x

We need a leading coefficient of  1

for completing the square, so factor out the current leading coefficient of 2.

y − 49 = 5 ( x 2 − 6 x )

Next, we need to add the correct number to both sides of the equation to create a perfect square. However, because the number will be placed inside the parenthesis on the right side we must factor it by  

2

on the left side of the equation. This is the coefficient we factored out in the previous step.

y − 49 + ( 5 ⋅ ? ) = 5 ( x 2 − 6 x + ? )

<- Hint:  

62 = 3 ;  3 ⋅ 3 = 9

y − 49 + ( 5 ⋅ 9 ) = 5 ( x 2 − 6 x + 9 )  

y− 49 + 45 = 5 ( x 2 − 6 x + 9 )

y − 4 = 5 ( x 2 − 6 x + 9 )

Then, we need to create the square on the right hand side of the equation:

y − 4 = 5 ( x − 3 ) 2

Now, isolate the  y  term:

y − 4 + 4 = 5 ( x − 3 ) 2 + 4

y − 0 = 5 ( x − 3 ) 2 + 4

y − 0 = 5 ( x − 3 ) 2 + 4

The vertex is:  

( 3 , 4 )

7 0
3 years ago
Fine the class width ​
WITCHER [35]

Answer:

class width is 5

Step-by-step explanation:

8 0
3 years ago
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