Answer:
24 chairs in each class needed
25 classrooms
700 chairs total
how many extra chairs
chairs will be c
t is total
t= 25×c
opposite of multiplication is division( 25 is multiplying by c) c needs to be alone
25 classrooms times chairs equal total chairs
t is 700
700=25×c
700/25=25/25c
700/25=C
c is 28
so 28 chairs for 25 classrooms
they need 24 chairs per class
so there are 4 extra chairs per class
4×25 is 100
**or just multiply 25 classes and 24 chairs
25 times 24 is 600
there are 700 chairs
100 left over
so 100 extra chairs
Answer:
x=3
Step-by-step explanation:
Simplify 3(x-2)+5X
= 8x-6=18
Add 6 to both sides
8x=24
Divide by 8
x=3
Answer:
y=2x+0
Step-by-step explanation:
Answer:
x=5.6
y=-5.6
Step-by-step explanation:
3x - 5y = 14 Equation 1
– 2x + 2y = 0 Equation 2
Simultaneous equation can be solved either through elimination method or substitution method. But we use elimination method for this question
Multiply equation 1 by -2 (the coefficient of x in equation 2) and multiply equation 2 with 3 (the coefficient of x in equation 1), so that x will have the same coefficient in the new equations, and easy to eliminate
-2(3x - 5y = 14)
-6x+10y=-28 Equation 3
3(– 2x + 2y = 0)
-6x+6y=0 Equation 4
Subtract equation 4 from 3 to eliminate x
-6x+10y=-28
-6x+6y=0
-6x-(-6x)=-6x+6x=0
10y-6y=5y
-28-0=-28
5y=-28
y=-28/5
y=-5.6
Substitute for y in equation 2
– 2x + 2y = 0
– 2x + 2(-5.6) = 0
-2x-11.2=0
-2x=11.2
x=-11.2/2
x=5.6
